Solve the following equation in the interval:
0 degrees (< or equal to) theta < 360 degrees
cos^2 (theta) - 1 = 0
cos^2 (theta) = 1
cos (theta) = sq. root (1)
therefore: (theta) = inverse cos (sq. root of 1)
therefore: (theta) = 0 degrees (1 solution)
this is the only solution as the interval does not include 360 degrees
for its solutions to the equation.
ok, is this answer correct then.
pleae could someone check. thanx.
i dont get that. i got one solution of (theta) = 0. this gives a value of 1 when i look on the graph. you are saying that:
(theta) = inverse cosine -(sqr. root of 1) is also another solution.
then this gives: (theta) = 180 as the other solution.
yes/ but i dont understand that. when i get (theta) = 0 as the first solution, on teh graph it gives a y value of 1. i then look across to see if tehre are any other values of (theta) thst give 1. 180 degrees gives -1 on the graph of y = sinx.
haven't you guessed who this is yet?
I think the name says it all...