# Maths Puzzles (help needed!)

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Hello There, I hope you are well!

For my second assignment I have been given some maths problems to solve.

I am finding difficulty in two of the problems:

The first is

If x does not equal 2 or 4, verify that

(x / x-4) + (3 / x-2) = x^2 + x - 12 / (x-4) (x-2)

- I have managed to do this OK but the second half of this problem states "And hence, or otherwise, find the values of x for which:

(x / x-4) + (3 / x-2) = 0

Which has stumped me.

The second problem is...

The magnitude of an earthquake is given on the Richter scale by the formula:

R = log (a / T) + B

in the usual notation

A certain earthquake has a magnitude measuring R = 5 on the Richter scale at a particular position where B= 6.8. What is the Richter scale measurement at the same position of an earthquake which is 10 times stronger than this (in the sense that a/T is 10 times its value when R = 5)?

That has also stumped me.

Any help/advice would be appreciated!!

Thank you

Louk

For my second assignment I have been given some maths problems to solve.

I am finding difficulty in two of the problems:

The first is

If x does not equal 2 or 4, verify that

(x / x-4) + (3 / x-2) = x^2 + x - 12 / (x-4) (x-2)

- I have managed to do this OK but the second half of this problem states "And hence, or otherwise, find the values of x for which:

(x / x-4) + (3 / x-2) = 0

Which has stumped me.

The second problem is...

The magnitude of an earthquake is given on the Richter scale by the formula:

R = log (a / T) + B

in the usual notation

A certain earthquake has a magnitude measuring R = 5 on the Richter scale at a particular position where B= 6.8. What is the Richter scale measurement at the same position of an earthquake which is 10 times stronger than this (in the sense that a/T is 10 times its value when R = 5)?

That has also stumped me.

Any help/advice would be appreciated!!

Thank you

Louk

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#3

(Original post by

Hello There, I hope you are well!

For my second assignment I have been given some maths problems to solve.

I am finding difficulty in two of the problems:

The first is

If x does not equal 2 or 4, verify that

(x / x-4) + (3 / x-2) = x^2 + x - 12 / (x-4) (x-2)

- I have managed to do this OK but the second half of this problem states "And hence, or otherwise, find the values of x for which:

(x / x-4) + (3 / x-2) = 0

Which has stumped me.

The second problem is...

The magnitude of an earthquake is given on the Richter scale by the formula:

R = log (a / T) + B

in the usual notation

A certain earthquake has a magnitude measuring R = 5 on the Richter scale at a particular position where B= 6.8. What is the Richter scale measurement at the same position of an earthquake which is 10 times stronger than this (in the sense that a/T is 10 times its value when R = 5)?

That has also stumped me.

Any help/advice would be appreciated!!

Thank you

Louk

**Louk**)Hello There, I hope you are well!

For my second assignment I have been given some maths problems to solve.

I am finding difficulty in two of the problems:

The first is

If x does not equal 2 or 4, verify that

(x / x-4) + (3 / x-2) = x^2 + x - 12 / (x-4) (x-2)

- I have managed to do this OK but the second half of this problem states "And hence, or otherwise, find the values of x for which:

(x / x-4) + (3 / x-2) = 0

Which has stumped me.

The second problem is...

The magnitude of an earthquake is given on the Richter scale by the formula:

R = log (a / T) + B

in the usual notation

A certain earthquake has a magnitude measuring R = 5 on the Richter scale at a particular position where B= 6.8. What is the Richter scale measurement at the same position of an earthquake which is 10 times stronger than this (in the sense that a/T is 10 times its value when R = 5)?

That has also stumped me.

Any help/advice would be appreciated!!

Thank you

Louk

For the second one, can you tell us what a, T and B represent?

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that's all i was given for the second question! thanks for your help on the first loads!!

Louk

Louk

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#5

(Original post by

that's all i was given for the second question! thanks for your help on the first loads!!

Louk

**Louk**)that's all i was given for the second question! thanks for your help on the first loads!!

Louk

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#6

(Original post by

Ok, say 5 = log(a/T) + 6.8, so log(a/T) = -1.8 so log (10a/T) = log 10 + log (a/T) = log 10 - 1.8 and the value of log 10 depends on your base (i assume you actually mean ln x?)

**theone**)Ok, say 5 = log(a/T) + 6.8, so log(a/T) = -1.8 so log (10a/T) = log 10 + log (a/T) = log 10 - 1.8 and the value of log 10 depends on your base (i assume you actually mean ln x?)

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#7

(Original post by

no its log to the base 10, thats the one they use for richter.

**elpaw**)no its log to the base 10, thats the one they use for richter.

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