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Mr_Smith
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#1
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#1
i got stuck on this p4 calculus equations. apperaently i have to 'solve it'. please could u giv me help and the method. here goes.....5y=15. i have to find the anwser for y???
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Ralfskini
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#2
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(Original post by Mr_Smith)
i got stuck on this p4 calculus equations. apperaently i have to 'solve it'. please could u giv me help and the method. here goes.....5y=15. i have to find the anwser for y???
hmmmmm
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Ralfskini
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(Original post by Mr_Smith)
i got stuck on this p4 calculus equations. apperaently i have to 'solve it'. please could u giv me help and the method. here goes.....5y=15. i have to find the anwser for y???
I would give up.
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Bigcnee
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#4
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#4
y=2
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Mr_Smith
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#5
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(Original post by Bigcnee)
y=2
yeh but whats the method? how do you get to that?
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guess_who
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OK, HERE GOES:

5y = 15
y = 15/5

Answer: y = 3

wow, i thought P4 Calculus would be harder than that.

BigMcnee you got it wrong man.
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Bigcnee
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(Original post by guess_who)
OK, HERE GOES:

5y = 15
y = 15/5

Answer: y = 3

wow, i thought P4 Calculus would be harder than that.

BigMcnee you got it wrong man.
Well, you ask a stupid question, you get a stupid answer.

5y = 15
5y/5 = 15/5
y = 2.17463
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Chuck D
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(Original post by guess_who)
OK, HERE GOES:

5y = 15
y = 15/5

Answer: y = 3

wow, i thought P4 Calculus would be harder than that.

BigMcnee you got it wrong man.

I got another GCSE A* question can anyone help.

A B and C are angles in a triangle. A = 60, B = 60. Find C
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Ralfskini
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5y = 15
5y + x = 15 + x
(5y + x)/2 = (15 + x)/2
((5y + x)/2)^2 = ((15 + x)/2)^2
((5y + x)/2)^2
(5y + x)/2 = (((15 + x)/2)^2)^1/2
5y + x = 2(((15 + x)/2)^2)^1/2)
5y = 2(((15 + x)/2)^2)^1/2) - x
y = 1/5*2(((15 + x)/2)^2)^1/2) - 1/5*x
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guess_who
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#10
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ok, here goes:

angles in triangle add up to 180 degrees always.

therefore: 180 degrees = 120 degrees - C
therefore: (180 - 120) degress = C
therefore: C = 60 degrees

or, you could realise that 60 + 60 + 60 = 180 as any1 would.
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guess_who
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#11
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#11
(Original post by Ralfskini)
5y = 15
5y + x = 15 + x
(5y + x)/2 = (15 + x)/2
((5y + x)/2)^2 = ((15 + x)/2)^2
((5y + x)/2)^2
(5y + x)/2 = (((15 + x)/2)^2)^1/2
5y + x = 2(((15 + x)/2)^2)^1/2)
5y = 2(((15 + x)/2)^2)^1/2) - x
y = 1/5*2(((15 + x)/2)^2)^1/2) - 1/5*x
lol, i always show people the ahrder way. thanks ralfskini..
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Professor Griff
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(Original post by guess_who)
ok, here goes:

angles in triangle add up to 180 degrees always.

therefore: 180 degrees = 120 degrees - C
therefore: (180 - 120) degress = C
therefore: C = 60 degrees

or, you could realise that 60 + 60 + 60 = 180 as any1 would.
slow down where'd ya get the 180 from? and wheres the 120 from?
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Bigcnee
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You do realise that this person is taking the p***?
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Professor Griff
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#14
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#14
(Original post by Bigcnee)
You do realise that this person is taking the p***?
what is this related? does the p*** have to be subtracted from the formula, someone plz help i don't understand
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Chuck D
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(Original post by Bigcnee)
You do realise that this person is taking the p***?
no really I need help. Just because your good at Maths and can do questions really easily, doesn't mean everyone else in the world is! We all have our own strengths and weaknesses, and my weakest subject is maths. Therefore something you find "piss easy", I could find very hard!
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Bigcnee
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(Original post by Chuck D)
no really I need help. Just because your good at Maths and can do questions really easily, doesn't mean everyone else in the world is! We all have our own strengths and weaknesses, and my weakest subject is maths. Therefore something you find "piss easy", I could find very hard!
Apologies.
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elpaw
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#17
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#17
(Original post by Mr_Smith)
i got stuck on this p4 calculus equations. apperaently i have to 'solve it'. please could u giv me help and the method. here goes.....5y=15. i have to find the anwser for y???
the answer is the real part of the complementary function of the following simultaneous differential equations:

dy/dx - 2 dz/dx + y + z - 2 = 0

3 dy/dx + dz/dx +y - z + 2 = 0
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PRIVATESKLGIRL
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#18
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#18
if u seriously find it hard then go to ur teacher and tell him/her u dont understand he cud give u extra lessons or help u after the lesson. you wont learn anything by just getting the answers.
But it is strange how you say there A* gcse questions when there quite easy and if they were A* type they would be harder ques. and if ur doing gcse maths. u shud know the answers or have a little clue about what the answer could be as you should of done that kind of maths when in the 3rd and 4th form. (yr 9 and 10)
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guess_who
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#19
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#19
Well, The Sentence:

All Angles In A Triangle Add Up To 180 Degrees Is Where The 180 Came From.

180 Degrees (all 3 Angles In Traingle) = (angle 1 ) + (angle 2) + (angle 3)

We Know 2 Angles. It Said A = 60, And B = 60

Therefore: 180 Degrees = 60 + 60 + Angle C
180 Degrees = 120 Degrees + C
We Need To Find Angle C, Therefore We Bring The 120 Degrees From The Right Side To The Left. Whenever We Reverse Something, I.e.) Swap The Side Its On, We Need To Reverse The Sign Infront Of The Value.

Therefore: 180 - 120 = Angle C
Which Solves: 60 Degrees = C

Understand. Or, If You Dont Get This "bringing The 120 From The Right Side To The Left Side", Then:

What Number Adds To 120 To Make Up 180.

Well Obviously Its 60, Therefore Angle C = 60 Degrees
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Ralfskini
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#20
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#20
(Original post by guess_who)
Well, The Sentence:

All Angles In A Triangle Add Up To 180 Degrees Is Where The 180 Came From.

180 Degrees (all 3 Angles In Traingle) = (angle 1 ) + (angle 2) + (angle 3)

We Know 2 Angles. It Said A = 60, And B = 60

Therefore: 180 Degrees = 60 + 60 + Angle C
180 Degrees = 120 Degrees + C
We Need To Find Angle C, Therefore We Bring The 120 Degrees From The Right Side To The Left. Whenever We Reverse Something, I.e.) Swap The Side Its On, We Need To Reverse The Sign Infront Of The Value.

Therefore: 180 - 120 = Angle C
Which Solves: 60 Degrees = C

Understand. Or, If You Dont Get This "bringing The 120 From The Right Side To The Left Side", Then:

What Number Adds To 120 To Make Up 180.

Well Obviously Its 60, Therefore Angle C = 60 Degrees
I cant believe you managed so many stages. An educated monkey could have understood it in a single step.
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