Xerophelistica
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#21
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#21
This thread contains the many tribulations of a TSR user
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kathryn195
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#22
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#22
you differentiate it, then put your answer equal to zero. Also this is on the normal IGCSE syllabus, cos i have my exam tomorrow and it is one of the topics i am revision
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Dingooose
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#23
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Attachment 458945458947Name:  minimum point.PNG
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Dingooose
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#24
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(Original post by M_E_X)
The minimum point will be when x = -4. You have to set the inside of the bracket to zero.

Sub x= -4 in to the original equation to find the value of the function at this point.

source: http://www.mathcentre.ac.uk/resource...ingsquare1.pdf (section 4)
The minimum point is at x = 4 not x = -4 though.
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Dingooose
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#25
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(Original post by jonny23563)
Differentiate, set this equal to 0 to find stationary points.

Check values either side of any stationary points to see whether they are minimum or maximum
There's no need to check. A quadratic graph has the shape of a parabola, and if the coefficient of x^2 is positive, it will only have one minimum point and no other stationary points.
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Sir Cumference
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#26
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(Original post by Dingooose)
There's no need to check. A quadratic graph has the shape of a parabola, and if the coefficient of x^2 is positive, it will only have one minimum point and no other stationary points.
I think you'll find plenty of new threads to reply to.

There's no need to resurrect a 6 year old thread
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Dingooose
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#27
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(Original post by notnek)
I think you'll find plenty of new threads to reply to.

There's no need to resurrect a 6 year old thread
Whoops, my bad.
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Alexion
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#28
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#28
Double necro! It got revived once more in 2012, he's just keeping the 3-year cycle going
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lunab1234
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#29
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#29
its as level
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Karina77
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#30
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The answer is (4,7) because the bracket needs to be zero so its the opposite sign therefore 4. And the y is the exact number at the end so 7.
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Mida.
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#31
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(Original post by jklmn)
You don't need to know that at gcse???
It's part of the syllabus now😂
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