The Student Room Group
anyone?
Reply 2
i think discrete uniform distribution is where each value of x has the same probablilty
i.e. x: 1 2 3 4
P(X=x): 1/4 1/4 1/4 1/4
so the mean is the middle value, 2.5 in this case. does that help?
Reply 3
ok see jbuck was right, a discrete uniform distribution has the same P(X=x) for all the values. the mean of a discrete uniform distribution would be E(X)
and the E(X) of a discrete uniform distribution is always the same as the probabilty. like if i have x values - 1,2,3,4,5
probability of each would be 1/5,1/5,1/5,1/5,1/5
therefore Mean[E(X)] would be 1/5
Reply 4
im not sure what you meant by that, how can the mean of 1 2 3 4 5 be 1/5?...
i think darkest knight means he has to work out E(X), which in the case of 1 2 3 4 5 would be 3
Reply 5
Its really easy to work out the mean when it is Discrete uniform distribution, you can just use this formula:

(n+1)2\frac{(n+1)}{2}

I think for the variance the formula is: (someone correct me if I'm wrong on this one, Im not sure)

(n+1)(n+2)2\frac{(n+1)(n+2)}{2}

Remember this only applies to Discrete uniform distribution, you cannot use this for discrete random variables that have different probablities.
I believe the Variance formula is:
(n+1)(n-1)/12