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One mathematical question on Diaphragm cell

I did the other questions like equations and explanation answers fine, but I was stuck on this mathematical one.

If someone can explain to me how it is to be worked out, I would really appreciate it!

Question:

Assuming 100% efficiency and a cell current of 150,000A, how long (in sensible time units) will it take to generate 10(to the power of 6) metres cubed of Hydrogen gas at RTP (Room Temperature)? (Take the charge on a mole of electrons to be 96,000 coulombs and the molar volume at RTP to be 24decimetres cubed)

What volume of chlorine gas might you expect to generate over the same time, and why would the actual value be somewhat less?


Thanks. :tsr:
volume occupied by a gas at RTP in cubic metres = 0.024

therfore moles of gas in 10^6 m3 =10^6/0.024 =4.166 x 10^7

one mole of chlorine requires 2 moles of electrons = 2 x 96000 coulombs =192000C

therefore coulombs needed = 4.166 x 10^7 x 192000C

as Q=It then time taken = Q/I

time taken = (4.166 x 10^7 x 192000C)/150000

which I make to be 1 year and 252 days!

better check it someone!
Reply 2
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theelite
OP
thanks!

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