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    • Thread Starter
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    I dont know how to use latex and i've only got a min so sorry about the formatting.
    Code:
    a_1=3
    a_(n+1)=3a_n-5
    
    that defines my series.
    
    Then I have
    5
    Sigma (3(a_n)-5)
    x=1
    

a_1=3
    

a_{n+1}=3an-5
    When inputting this into the calculator, is there any way to specify the starting value? ie a_1?
    • PS Helper
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    PS Helper
    What are you trying to calculate? If you have the series with starting value 3 where a_{n+1}=3a_n-5 then you can just put 3 into your calculator and use the Ans key in place of a_n to find a_{n+1}.
    • Thread Starter
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    Its the sum of the series that I need to calulate. It was todays exam. But either way, it would be nice to know. Its just how to set the starting value of 3 instead of 1
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    http://www.thestudentroom.co.uk/wiki...1ES_Calculator

    Look here.
 
 
 
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