The Hardest Log Question in the World..

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loveisjustasong
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#1
Report Thread starter 11 years ago
#1
right now, to me.

Calculate y for which 2log3 y - log3 (y+4) = 2

I expanded and got 2log3 y - ylog3 + 4log3 = 2

But I have no clue what to do next?

Do I do 2 - 4log3 ?
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darkness9999
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#2
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How about this?

\log_3 \frac{y^2}{y+4} = 2
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loveisjustasong
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That's so much better...> why didn't I think to do that!
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loveisjustasong
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#4
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#4
Thank you!
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username246000
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#5
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Is 4log3 the sam as log(3^4) , though not too sure, not done C2 sice last year jan
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pesking2009
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#6
y2/y+4=2 remember the division-minus rule, log3-log3=log3/3
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pesking2009
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and ylog3=log3^y
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darkness9999
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#8
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(Original post by pesking2009)
y2/y+4=2 remember the division-minus rule, log3-log3=log3/3
:nope:

=====>  \frac{y^2}{y+4}=3^2
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mfc20
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#9
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Lol at the thread title bit of an anticlimax :P GOod to see it get solved though on a serious note!
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Bluebird92
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#10
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I would have been able to help with this, but I haven't done C2 since over an hour ago
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refref
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#11
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#11
log3(9) = 2
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Ewan
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#12
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#12
Whats with the sudden influx of log questions all of a sudden o_O
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refref
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#13
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(Original post by Ewan)
Whats with the sudden influx of log questions all of a sudden o_O
c2 exam coming up and lots of people have trouble with logs.

I think the log questions in the actual C2 exams are rather easy though.

The mixed exercise in edexcel for logs is quite hard too.
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DCalfine
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#14
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Dam, I just had my C2 exam for the OCR paper. And my god, I feel like there's no hope.
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Lawsonoluwaseun
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#15
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#15
You cancel out the like logs since it is. In base ten u cancel log3 out
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TeeEm
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#16
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#16
(Original post by Lawsonoluwaseun)
You cancel out the like logs since it is. In base ten u cancel log3 out
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Student403
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#17
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#17
(Original post by TeeEm)
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Hahahaha so true
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Student403
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#18
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#18
(Original post by TeeEm)
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Reminds me of when someone said, once differentiated to f'(x) = dy/dx, you can cancel the ds and get y = xf'(x)
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Vikingninja
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#19
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#19
This thread is 6 years old.
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username2130115
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#20
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#20
nice clickbait
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