The Hardest Log Question in the World..

right now, to me.

Calculate y for which 2log3 y - log3 (y+4) = 2

I expanded and got 2log3 y - ylog3 + 4log3 = 2

But I have no clue what to do next?

Do I do 2 - 4log3 ? :frown:

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Reply 1

darkness9999

How about this?

$\log_3 \frac{y^2}{y+4} = 2$

Reply 2

loveisjustasong

That's so much better...> :frown:

why didn't I think to do that!

Reply 3

loveisjustasong

Thank you!

Reply 4

username246000

Is 4log3 the sam as log(3^4) , though not too sure, not done C2 sice last year jan

Reply 5

pesking2009

y2/y+4=2 remember the division-minus rule, log3-log3=log3/3

Reply 6

pesking2009

and ylog3=log3^y

Reply 7

darkness9999

pesking2009

y2/y+4=2 remember the division-minus rule, log3-log3=log3/3

=====> $\frac{y^2}{y+4}=3^2$

Reply 8

mfc20

Lol at the thread title bit of an anticlimax :P GOod to see it get solved though on a serious note!

Reply 9

Bluebird92

I would have been able to help with this, but I haven't done C2 since over an hour ago :biggrin:

Reply 10

refref

log3(9) = 2

Reply 11

Ewan

Whats with the sudden influx of log questions all of a sudden o_O

Reply 12

refref

Ewan

Whats with the sudden influx of log questions all of a sudden o_O

c2 exam coming up and lots of people have trouble with logs.

I think the log questions in the actual C2 exams are rather easy though.

The mixed exercise in edexcel for logs is quite hard too.