A Simple AS Level Question Watch

aura1947
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#1
Report Thread starter 9 years ago
#1
http://www.planet-master.com/Interna..._w08_qp_32.pdf

If someone could explain how to answer Q1. (c). I'd be awfully thankful.
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Woody.
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#2
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#2
n = M/Mr
M = 28.44
Mr (KMnO4) = 158

28.44/158 = 0.18 mol
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aura1947
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#3
Report Thread starter 9 years ago
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(Original post by Woody.)
n = M/Mr
M = 28.44
Mr (KMnO4) = 158

28.44/158 = 0.18 mol
Sorry, that's incorrect. But thanks for your time.

I found out how to solve this.
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Woody.
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#4
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#4
(Original post by aura1947)
Sorry, that's incorrect. But thanks for your time.

I found out how to solve this.
What was the solution?
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aura1947
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#5
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#5
(Original post by Woody.)
What was the solution?
c = (g/dm^3) / Mr

n = c * v

i.e. n = ((g/dm^3) / Mr) * v

g/dm^3 = 28.44
Mr = 158
and assuming 0.042 dm^3 was transferred

n = ((28.44) / 158) * 0.042
n = 7.56*10^-3 mol

That's the answer.
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