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Hey Ive got a cambridge interview at Girton College in 2 weeks for maths does anyone know what type of questions i will get asked in the test before or the 2 interviews. Please help me im so screwed otherwise

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robert_harrison

Hey Ive got a cambridge interview at Girton College in 2 weeks for maths does anyone know what type of questions i will get asked in the test before or the 2 interviews. Please help me im so screwed otherwise

I just know one question, e to the power of pi, pi to the power of e, which one is bigger, without using a calculator. and show how you work it out

ZJuwelH

What the hell, I'm also going for Maths at Girton! My interview is the 7th...

As for pi^e or e^pi, where my calculator at?! Then I can work out how to work it out...

As for pi^e or e^pi, where my calculator at?! Then I can work out how to work it out...

You can try to sketch two graph in the same x,y-cordinates,they are e to the power of x, and x to the power of e, they will meet when x=e, but you should also aware that there are two kind of " meeting", one is crossing, the other is touching, you should also work out the derivative of two functions at x=e, you will find they are the same, so the just touch each other tangentially, then try draw a line x=pi, you will get the answer!

But couldn't you do it like:

e<3 and pi>3, so if we had x^y then we could bung in numbers that are proxies for e and pi so that the proxies are less than and greater than (or equal to?) 3 respectively. Using this 2^3 gives 8, and 3^2 gives 9, so pi^e > e^pi...

Sounds so stupid and basic doesn't it...

e<3 and pi>3, so if we had x^y then we could bung in numbers that are proxies for e and pi so that the proxies are less than and greater than (or equal to?) 3 respectively. Using this 2^3 gives 8, and 3^2 gives 9, so pi^e > e^pi...

Sounds so stupid and basic doesn't it...

you can prove it as follows:

You draw a graph with e^x and x^e. At x=e, both graph touch/cross.

With first deviation you find out that they touch. so they rise at same rate in this point. But as

1.) x^e (which represents the graph on which pi^e is situated at x=pi in this case) is a function where the exponent stays the same all the time, and

2.) e^x (representing e^pi for x=pi) where the exponent rises as x rises, the function e^x will have an increased gradient, thus be higher than x^e when x>e. As x=pi in our problem, and pi>e, we can say that e^pi is a larger number than pi^e.

You draw a graph with e^x and x^e. At x=e, both graph touch/cross.

With first deviation you find out that they touch. so they rise at same rate in this point. But as

1.) x^e (which represents the graph on which pi^e is situated at x=pi in this case) is a function where the exponent stays the same all the time, and

2.) e^x (representing e^pi for x=pi) where the exponent rises as x rises, the function e^x will have an increased gradient, thus be higher than x^e when x>e. As x=pi in our problem, and pi>e, we can say that e^pi is a larger number than pi^e.

so in an interview, u r given grapg paper and time to draw a graph

2776

For Cambridge science, you are given paper to do workings

Talk about on the spot.

2776

Some of the questions are rock. Like work out what happens when a piston of circlar area of x cm^3 is pushed 10cm. How much pressure is extered. Or something like this.

area would be cm^2...i take it that was not a proper q :-)

how do u do that then?

i suppose u could say:

must all be odd no's: three consecutive odd numbers will have one which is a mulitple of three so therefore 3,5,7 is only possible trio

must all be odd no's: three consecutive odd numbers will have one which is a mulitple of three so therefore 3,5,7 is only possible trio

every third odd number is divisible by three

lgs98jonee

how do u do that then?

It'a case of saying that a set of triple primes will be in the form

n, n + 2, n + 4

and in a set of three consecutive integers you have

n, n + 1, n + 2

one must be divisible by three

n and n + 2 cannot be divisible by three if these numbers appear in a set of triple primes (unless n = 3)

so n + 1 must be divisible by three, but if n +1 is divisible by three then n + 4 must be, and so n + 4 is not prime unless n = 3, which is why 3,5,7 is the only set.

- Why is the entrance rate for maths at Oxford so low?
- What should I do
- What to do for a competitive application for Mathematics at top universities.
- Cambridge maths Vs CS .
- Applying to cambridge
- Maths at Cambridge
- Cambridge maths
- Gap year applicant, style of interview
- Do Trinity College, Cambridge students get any work advantages?
- To those in Cambridge
- Cambridge Chemical engineering and biotechnology
- should i apply to oxford or cambridge?
- Oxford or Cambridge med?
- Oxbridge interview for maths
- Esat stress
- Cambridge med
- For those in Cambridge
- Math at Cambridge
- Can I get into oxbrdige with pefect A-levels but no GCSEs?
- Can the TMUA negate poor GCSE performance?

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