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# cambridge interview for maths watch

1. (Original post by integral_neo)
didnt know that tan (x/2) will work as well.. how did u realise this?
It's a pretty common method for integrating with a number and a linear (i.e. no powers) trig function in the denominator if it's not obvious how to do it.
2. (Original post by theone)
It's a pretty common method for integrating with a number and a linear (i.e. no powers) trig function in the denominator if it's not obvious how to do it.
Are you doing Edexcel maths and F maths? what modules have u taken and what UMS did u get for each and which ones u will taking in June? r u gonna do extension paper?

do this one:

r = 3cox(2x)

find the length between the two parallel (to the initial line) tangents to the graph
3. (Original post by JamesF)
For the first one, write the consecutive numbers
n(n+1)(n+2)(n+3), then if n is odd, n+1, and n+3 are multiples of 2. Either n+1 or n+3 is a multiple of 4. n or n+2 must be a multiple of 3.

n - even. Same arguements.

2) A great trick i read. The highest power of a prime into a factorial is found as follows.
Sum from i=1 to infinity of [20/2^i]
Where [x] is the greatest integer function.

Lol, except it doesnt seem to work.
is i supposed to be sqrt(-1)?
wot year u in james?
4. (Original post by integral_neo)
Are you doing Edexcel maths and F maths? what modules have u taken and what UMS did u get for each and which ones u will taking in June? r u gonna do extension paper?

do this one:

r = 3cox(2x)

find the length between the two parallel (to the initial line) tangents to the graph
I'm not going to go through this again I remember it from my P4 exam and took me half a side and I don't have time to regurgitate. I'll pm my marks/modules.
5. (Original post by theone)
I'm not going to go through this again I remember it from my P4 exam and took me half a side and I don't have time to regurgitate. I'll pm my marks/modules.
lolllll I spent so much time on it and got the right equation after differentiation but i just couldnt solve that equation then that was the only question i messed up on P4
6. No, i is not sqrt(-1). Read what i said about the sum. Using it for this question we get

k = (sum from i=1 to infinity) [20/2^i]
2^5 > 20 so we only need to consider the cases, when i is 1,2,3,4.
[20/2] = 10
[20/4] = 5
[20/8] = 2
[20/16] = 1

Sum these, 10+5+2+1 = 18.

Im in Lower 6th.
7. For the second part of that question. For 10's to divide 20!, 2 and 5 must divide, so the highest power of 10 to divide 20! depends on the power of 5's to divide 20!, since there will be a higher number of 2's than 5's.

20/5 = 4
[20/25] = 0
8. (Original post by JamesF)
For the second part of that question. For 10's to divide 20!, 2 and 5 must divide, so the highest power of 10 to divide 20! depends on the power of 5's to divide 20!, since there will be a higher number of 2's than 5's.

20/5 = 4
[20/25] = 0
the answers to both questions are indeed right
9. (Original post by JamesF)
For the second part of that question. For 10's to divide 20!, 2 and 5 must divide, so the highest power of 10 to divide 20! depends on the power of 5's to divide 20!, since there will be a higher number of 2's than 5's.

20/5 = 4
[20/25] = 0
that is v. good...have u been taught that then? is so, wot module?
10. james did u do the maths challenge?
11. It was in some university lecture notes on elementary number theory.
12. (Original post by JamesF)
It was in some university lecture notes on elementary number theory.
wow....where did u get them from and did u do the senior maths challenge?
13. No I didnt do SMC.
I cant remember where i found them, but google will throw up loads of stuff if you search.

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