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    (Original post by integral_neo)
    didnt know that tan (x/2) will work as well.. how did u realise this?
    It's a pretty common method for integrating with a number and a linear (i.e. no powers) trig function in the denominator if it's not obvious how to do it.
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    (Original post by theone)
    It's a pretty common method for integrating with a number and a linear (i.e. no powers) trig function in the denominator if it's not obvious how to do it.
    Are you doing Edexcel maths and F maths? what modules have u taken and what UMS did u get for each and which ones u will taking in June? r u gonna do extension paper?

    do this one:

    r = 3cox(2x)

    find the length between the two parallel (to the initial line) tangents to the graph
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    (Original post by JamesF)
    For the first one, write the consecutive numbers
    n(n+1)(n+2)(n+3), then if n is odd, n+1, and n+3 are multiples of 2. Either n+1 or n+3 is a multiple of 4. n or n+2 must be a multiple of 3.

    n - even. Same arguements.

    2) A great trick i read. The highest power of a prime into a factorial is found as follows.
    Sum from i=1 to infinity of [20/2^i]
    Where [x] is the greatest integer function.

    Lol, except it doesnt seem to work.
    is i supposed to be sqrt(-1)?
    wot year u in james?
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    (Original post by integral_neo)
    Are you doing Edexcel maths and F maths? what modules have u taken and what UMS did u get for each and which ones u will taking in June? r u gonna do extension paper?

    do this one:

    r = 3cox(2x)

    find the length between the two parallel (to the initial line) tangents to the graph
    I'm not going to go through this again I remember it from my P4 exam and took me half a side and I don't have time to regurgitate. I'll pm my marks/modules.
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    (Original post by theone)
    I'm not going to go through this again I remember it from my P4 exam and took me half a side and I don't have time to regurgitate. I'll pm my marks/modules.
    lolllll I spent so much time on it and got the right equation after differentiation but i just couldnt solve that equation then that was the only question i messed up on P4
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    No, i is not sqrt(-1). Read what i said about the sum. Using it for this question we get

    k = (sum from i=1 to infinity) [20/2^i]
    2^5 > 20 so we only need to consider the cases, when i is 1,2,3,4.
    [20/2] = 10
    [20/4] = 5
    [20/8] = 2
    [20/16] = 1

    Sum these, 10+5+2+1 = 18.

    Im in Lower 6th.
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    For the second part of that question. For 10's to divide 20!, 2 and 5 must divide, so the highest power of 10 to divide 20! depends on the power of 5's to divide 20!, since there will be a higher number of 2's than 5's.

    20/5 = 4
    [20/25] = 0
    So the answer is 4.
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    (Original post by JamesF)
    For the second part of that question. For 10's to divide 20!, 2 and 5 must divide, so the highest power of 10 to divide 20! depends on the power of 5's to divide 20!, since there will be a higher number of 2's than 5's.

    20/5 = 4
    [20/25] = 0
    So the answer is 4.
    the answers to both questions are indeed right
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    (Original post by JamesF)
    For the second part of that question. For 10's to divide 20!, 2 and 5 must divide, so the highest power of 10 to divide 20! depends on the power of 5's to divide 20!, since there will be a higher number of 2's than 5's.

    20/5 = 4
    [20/25] = 0
    So the answer is 4.
    that is v. good...have u been taught that then? is so, wot module?
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    james did u do the maths challenge?
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    It was in some university lecture notes on elementary number theory.
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    (Original post by JamesF)
    It was in some university lecture notes on elementary number theory.
    wow....where did u get them from and did u do the senior maths challenge?
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    No I didnt do SMC.
    I cant remember where i found them, but google will throw up loads of stuff if you search.
 
 
 
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