Integration question Watch

charlottebox
Badges: 0
#1
Report Thread starter 9 years ago
#1
Hi, can anyone help with this integration question, sorry I don't know how to write the symbols.

What is the integral (from 0 to pi/2) of

cosx / [1 + (sinx)^2]

I've tried loads of things but nothing is working! Thanks.
0
reply
nuodai
Badges: 14
#2
Report 9 years ago
#2
Use the substitution u = \sin x, and then the cos x on the top of the fraction will cancel when you multiply by dx/du. You then need to use the standard result for an integral of the form \dfrac{1}{1+u^2} (don't use logs, please :p:).
0
reply
charlottebox
Badges: 0
#3
Report Thread starter 9 years ago
#3
Of course! thanks.
0
reply
Siddd
Badges: 0
Rep:
?
#4
Report 9 years ago
#4



See what I did there
0
reply
qgujxj39
Badges: 15
#5
Report 9 years ago
#5
(Original post by Siddd)



See what I did there
I'm loving wolfram alpha at the moment.
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Cardiff Metropolitan University
    Undergraduate Open Day - Llandaff Campus Undergraduate
    Sat, 27 Apr '19
  • University of East Anglia
    Could you inspire the next generation? Find out more about becoming a Primary teacher with UEA… Postgraduate
    Sat, 27 Apr '19
  • Anglia Ruskin University
    Health, Education, Medicine and Social Care; Arts, Humanities and Social Sciences; Business and Law; Science and Engineering Undergraduate
    Sat, 27 Apr '19

Have you registered to vote?

Yes! (543)
37.79%
No - but I will (112)
7.79%
No - I don't want to (98)
6.82%
No - I can't vote (<18, not in UK, etc) (684)
47.6%

Watched Threads

View All