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1. solve for the interval 0<= theta <= 360:

3Sin^2 theta + sin theta = 0

Any help iz very much appreciated.

Tut
2. 3Sin² theta + sin theta = 0
take y = [email protected]
3y² + y = 0
y(3y+1) = 0
y = 0 or y = -1/3
==> [email protected] = 0 or [email protected] = -1/3
3. solve for the interval 0<= theta <= 360:

3Sin^2 theta + sin theta = 0

use the quadratic formula to get the values of sinpheta = ??

sin^-1 on each side will give the solutions

then use 180 minus pheta, +360 pehta to get all the values

or do it the quick way like yazan did
4. f(x)=3(([email protected])^2)[email protected]=0

=>[email protected]([email protected]+1)=0

=>f(x)=0=>[email protected]=0 OR [email protected]=-(1/3)

[email protected]=0=>@=0, 180, 360

[email protected]=-(1/3)=-20, (-20+180)=160, (160+180)=340

=>@=0, 160, 180, 340, 360

Newton.

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