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    solve for the interval 0<= theta <= 360:

    3Sin^2 theta + sin theta = 0

    Any help iz very much appreciated.

    Tut
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    3Sin² theta + sin theta = 0
    take y = [email protected]
    3y² + y = 0
    y(3y+1) = 0
    y = 0 or y = -1/3
    ==> [email protected] = 0 or [email protected] = -1/3
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    solve for the interval 0<= theta <= 360:

    3Sin^2 theta + sin theta = 0

    use the quadratic formula to get the values of sinpheta = ??

    sin^-1 on each side will give the solutions

    then use 180 minus pheta, +360 pehta to get all the values

    or do it the quick way like yazan did
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    f(x)=3(([email protected])^2)[email protected]=0

    =>[email protected]([email protected]+1)=0

    =>f(x)=0=>[email protected]=0 OR [email protected]=-(1/3)

    [email protected]=0=>@=0, 180, 360

    [email protected]=-(1/3)=-20, (-20+180)=160, (160+180)=340

    =>@=0, 160, 180, 340, 360

    Newton.
 
 
 
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