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lollipop
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Report Thread starter 16 years ago
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Heres a Q that I cant seem to get my head round, and I was wondering if anyone would be able to help!

The change in momentum of a 0.045Kg ball during the time of contact is approx 2kgm/s. Calculate the speed of the ball at the instant it leaves the club

Ive been told the working is 2/0.045 = 44m/s

The thing is, I always thought CHANGE IN MOMENTUM = 2MV (provided the collision was elastic, which in this case it is)...so it would be 2/(2 x 0.045).....

Its a simple Q with a simple answer - though i can't seem to find the answer!!!

Please help!!
Thankyou
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elpaw
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Report 16 years ago
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(Original post by lollipop)
Heres a Q that I cant seem to get my head round, and I was wondering if anyone would be able to help!

The change in momentum of a 0.045Kg ball during the time of contact is approx 2kgm/s. Calculate the speed of the ball at the instant it leaves the club

Ive been told the working is 2/0.045 = 44m/s

The thing is, I always thought CHANGE IN MOMENTUM = 2MV (provided the collision was elastic, which in this case it is)...so it would be 2/(2 x 0.045).....

Its a simple Q with a simple answer - though i can't seem to find the answer!!!

Please help!!
Thankyou
you are right
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lollipop
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#3
Report Thread starter 16 years ago
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so my teacher is wrong?.....

LOL,If so- great.....he already doesnt like me, this will finish it off!
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