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    Heres a Q that I cant seem to get my head round, and I was wondering if anyone would be able to help!

    The change in momentum of a 0.045Kg ball during the time of contact is approx 2kgm/s. Calculate the speed of the ball at the instant it leaves the club

    Ive been told the working is 2/0.045 = 44m/s

    The thing is, I always thought CHANGE IN MOMENTUM = 2MV (provided the collision was elastic, which in this case it is)...so it would be 2/(2 x 0.045).....

    Its a simple Q with a simple answer - though i can't seem to find the answer!!!

    Please help!!
    Thankyou
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    (Original post by lollipop)
    Heres a Q that I cant seem to get my head round, and I was wondering if anyone would be able to help!

    The change in momentum of a 0.045Kg ball during the time of contact is approx 2kgm/s. Calculate the speed of the ball at the instant it leaves the club

    Ive been told the working is 2/0.045 = 44m/s

    The thing is, I always thought CHANGE IN MOMENTUM = 2MV (provided the collision was elastic, which in this case it is)...so it would be 2/(2 x 0.045).....

    Its a simple Q with a simple answer - though i can't seem to find the answer!!!

    Please help!!
    Thankyou
    you are right
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    so my teacher is wrong?.....

    LOL,If so- great.....he already doesnt like me, this will finish it off!
 
 
 
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