# complex numberWatch

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Thread starter 13 years ago
#1
how do i find the complex number such that arg(z-1)=pi/6 and |z-3|=2

i know that theyre a line and a circle but how do i know where they meet?

thanks alot
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13 years ago
#2
(Original post by sarah12345)
how do i find the complex number such that arg(z-1)=pi/6 and |z-3|=2

i know that theyre a line and a circle but how do i know where they meet?

thanks alot
Find their cartesian equations and hence find the point of intersect.
You know that the first one is a line passing through (1,0) with gradient tan(pi/6) [Though when you find points of intersection you need to take into account that for the line x>0, y>0 as it is in the first quadrant only and any equation you find with run through multiple].
The equation of the second stipulation is simple.
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Thread starter 13 years ago
#3
cheers dude
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