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phiyahless
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#1
Report Thread starter 16 years ago
#1
This is probably really simple bt iv forgotten hw u do it...

Use integration by parts 2 find the exact value of

∫ x² lnx dx

with limits 3 and 1


thanx
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yazan_l
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#2
Report 16 years ago
#2
I = ∫ x² lnx dx = ∫ x . xlnx dx

I = ½ x³ lnx - ∫x²/2 dx - 1/2 ∫x²lnx dx
I = ½ x³ lnx - x³/6 - 1/2 I
3/2 I = ½ x³ lnx - x³/6
I = ⅓ x³ lnx - x³/9


correct me if i'm wrong!
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phiyahless
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#3
Report Thread starter 16 years ago
#3
I don't know if it's right or wrong but thanx for the help!
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Fermat
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#4
Report 16 years ago
#4
I = ∫ x² lnx dx
I = (1/3) x³ lnx - (1/3)∫ x² dx
I = (1/3)x³ lnx - x³/6
I = (1/9)x³{3lnx - 1)
===============
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yazan_l
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#5
Report 16 years ago
#5
ya it's right! it's the same as fermat's
to err is human
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