Turn on thread page Beta
    • Thread Starter
    Offline

    2
    ReputationRep:
    I don't have the answer to this particular, indefinite integral, and I need to know if I've got it right. Also, I can't find it anywhere on the internet!

    The answer I get is:

    1/2 [sin(x)cosh(x) - cos(x)sinh(x)] + C

    Thanks,

    Ben
    Offline

    4
    ReputationRep:
    42
    Offline

    1
    ReputationRep:
    (Original post by Lord Huntroyde)
    42
    LOL!!!
    Offline

    18
    ReputationRep:
    Huntroyde, you get your sig quotes from Private Eye don't you!
    Offline

    4
    ReputationRep:
    (Original post by ZJuwelH)
    Huntroyde, you get your sig quotes from Private Eye don't you!
    Ondeed I do, but my purchasing of P.E. Mediaballs today will mean I can change quotes more than just fortnightly.
    Offline

    18
    ReputationRep:
    I would know this if I knew the integral of sinhx, or what sinhx was for that matter. But I think the integral of sinx is -cosx...
    Offline

    2
    ReputationRep:
    Could it be -1/h cos (hx) + C?
    Offline

    2
    ReputationRep:
    Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by Linda)
    Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?
    You actually have helped a bit. I accidentally omitted the constant of integration - thanks.

    Ben
    • Thread Starter
    Offline

    2
    ReputationRep:
    Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).

    Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

    Ben
    Offline

    0
    ReputationRep:
    (Original post by Ben.S.)
    Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).

    Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

    Ben
    please tell me that's P6 :confused: (I'm only doing up to P5 this year)
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by king of swords)
    please tell me that's P6 :confused: (I'm only doing up to P5 this year)
    It's complex numbers.
    Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!

    Ben
    Offline

    18
    ReputationRep:
    (Original post by king of swords)
    please tell me that's P6 :confused: (I'm only doing up to P5 this year)
    Better not be P6, I'm doing that!

    I saw all that and thought: in the words of Snoop Dogg, "wha-wha-wha-whaaaaaaa???"
    Offline

    2
    ReputationRep:
    (Original post by Ben.S.)
    It's complex numbers.
    Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!

    Ben
    If you differentiated it, it wouldn't be +c, now would it?
    Offline

    0
    ReputationRep:
    (Original post by Linda)
    If you differentiated it, it wouldn't be +c, now would it?
    ok so he did a hybrid of integration and differentiation lol
    Offline

    18
    ReputationRep:
    (Original post by king of swords)
    ok so he did a hybrid of integration and differentiation lol
    Intentiation or differegration... Newton and Fermat would be turning in their graves...
    Offline

    14
    ReputationRep:
    i think hyperbolic functions are p5.

    im only going up to p4, thank god :]
    Offline

    1
    ReputationRep:
    (Original post by Ben.S.)
    Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

    Ben
    huh?
    what is h?
    Offline

    0
    ReputationRep:
    The answer is:

    (sinxcoshx-cosxsinhx)/2
    • Thread Starter
    Offline

    2
    ReputationRep:
    (Original post by icy)
    huh?
    what is h?
    Right, so I've got my new, improved (non-dintegrated) answer now!

    I didn't do further - do you do hyperbolics like that?
    The 'h' just means that we aren't dealing with sines and cosines any more.

    Ben
 
 
 
Turn on thread page Beta
Updated: August 20, 2004

University open days

  1. Norwich University of the Arts
    Postgraduate Open Days Postgraduate
    Thu, 19 Jul '18
  2. University of Sunderland
    Postgraduate Open Day Postgraduate
    Thu, 19 Jul '18
  3. Plymouth College of Art
    All MA Programmes Postgraduate
    Thu, 19 Jul '18
Poll
How are you feeling in the run-up to Results Day 2018?
Useful resources

Make your revision easier

Maths

Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

Equations

How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.