What's the integral of sin(x)sinh(x)?

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Ben.S.
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#1
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#1
I don't have the answer to this particular, indefinite integral, and I need to know if I've got it right. Also, I can't find it anywhere on the internet!

The answer I get is:

1/2 [sin(x)cosh(x) - cos(x)sinh(x)] + C

Thanks,

Ben
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LH
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42
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Adhsur
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#3
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(Original post by Lord Huntroyde)
42
LOL!!!
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Juwel
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Huntroyde, you get your sig quotes from Private Eye don't you!
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LH
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(Original post by ZJuwelH)
Huntroyde, you get your sig quotes from Private Eye don't you!
Ondeed I do, but my purchasing of P.E. Mediaballs today will mean I can change quotes more than just fortnightly.
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Juwel
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I would know this if I knew the integral of sinhx, or what sinhx was for that matter. But I think the integral of sinx is -cosx...
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Linda
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Could it be -1/h cos (hx) + C?
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Linda
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#8
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Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?
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Ben.S.
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(Original post by Linda)
Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?
You actually have helped a bit. I accidentally omitted the constant of integration - thanks.

Ben
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Ben.S.
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#10
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Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).

Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

Ben
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king of swords
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(Original post by Ben.S.)
Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).

Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

Ben
please tell me that's P6 :confused: (I'm only doing up to P5 this year)
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Ben.S.
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(Original post by king of swords)
please tell me that's P6 :confused: (I'm only doing up to P5 this year)
It's complex numbers.
Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!

Ben
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Juwel
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(Original post by king of swords)
please tell me that's P6 :confused: (I'm only doing up to P5 this year)
Better not be P6, I'm doing that!

I saw all that and thought: in the words of Snoop Dogg, "wha-wha-wha-whaaaaaaa???"
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Linda
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(Original post by Ben.S.)
It's complex numbers.
Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!

Ben
If you differentiated it, it wouldn't be +c, now would it?
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king of swords
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(Original post by Linda)
If you differentiated it, it wouldn't be +c, now would it?
ok so he did a hybrid of integration and differentiation lol
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Juwel
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(Original post by king of swords)
ok so he did a hybrid of integration and differentiation lol
Intentiation or differegration... Newton and Fermat would be turning in their graves...
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kikzen
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i think hyperbolic functions are p5.

im only going up to p4, thank god :]
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icy
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#18
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(Original post by Ben.S.)
Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]

Ben
huh?
what is h?
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mikesgt2
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#19
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#19
The answer is:

(sinxcoshx-cosxsinhx)/2
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Ben.S.
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#20
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(Original post by icy)
huh?
what is h?
Right, so I've got my new, improved (non-dintegrated) answer now!

I didn't do further - do you do hyperbolics like that?
The 'h' just means that we aren't dealing with sines and cosines any more.

Ben
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