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What's the integral of sin(x)sinh(x)?
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Ben.S.
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#1
I don't have the answer to this particular, indefinite integral, and I need to know if I've got it right. Also, I can't find it anywhere on the internet!
The answer I get is:
1/2 [sin(x)cosh(x) - cos(x)sinh(x)] + C
Thanks,
Ben
The answer I get is:
1/2 [sin(x)cosh(x) - cos(x)sinh(x)] + C
Thanks,
Ben
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LH
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#2
Adhsur
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#3
Juwel
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#4
LH
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#5
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#5
(Original post by ZJuwelH)
Huntroyde, you get your sig quotes from Private Eye don't you!
Huntroyde, you get your sig quotes from Private Eye don't you!
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Juwel
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#6
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#6
I would know this if I knew the integral of sinhx, or what sinhx was for that matter. But I think the integral of sinx is -cosx...
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Linda
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#7
Linda
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#8
Ben.S.
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#9
(Original post by Linda)
Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?
Nevermind, mis read your question. What do you mean exactly? sin^2(x)or what?
Ben
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Ben.S.
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#10
Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).
Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]
Ben
Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]
Ben
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king of swords
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#11
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#11
(Original post by Ben.S.)
Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).
Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]
Ben
Sinh(x) is a hyperbolic function and, unfortunately, is not sin(hx).
Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]
Ben
(I'm only doing up to P5 this year)
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Ben.S.
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#12
(Original post by king of swords)
please tell me that's P6
(I'm only doing up to P5 this year)
please tell me that's P6
(I'm only doing up to P5 this year)
Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!
Ben
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Juwel
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#13
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#13
(Original post by king of swords)
please tell me that's P6 (I'm only doing up to P5 this year)
please tell me that's P6
(I'm only doing up to P5 this year)
I saw all that and thought: in the words of Snoop Dogg, "wha-wha-wha-whaaaaaaa???"
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Linda
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#14
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#14
(Original post by Ben.S.)
It's complex numbers.
Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!
Ben
It's complex numbers.
Oh, and it's absolute rubbish what I've written - I only bloody DIFFERENTIATED THE FLIPPING THING!!!!!
Ben
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king of swords
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#15
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#15
(Original post by Linda)
If you differentiated it, it wouldn't be +c, now would it?
If you differentiated it, it wouldn't be +c, now would it?
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Juwel
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#16
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#16
(Original post by king of swords)
ok so he did a hybrid of integration and differentiation lol
ok so he did a hybrid of integration and differentiation lol
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kikzen
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#17
icy
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#18
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#18
(Original post by Ben.S.)
Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]
Ben
Sin(x) = 1/2i[e^(ix) - e^(-ix)] and sinh(x) = 1/2[e^(x) - e^(-x)]
Ben
what is h?
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mikesgt2
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#19
Ben.S.
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#20
(Original post by icy)
huh?
what is h?
huh?
what is h?
I didn't do further - do you do hyperbolics like that?
The 'h' just means that we aren't dealing with sines and cosines any more.
Ben
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