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biology coursework 4 2morow!!!help gcse
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tinkabell
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can ne 1 tell me how to work out average percentage change in mass 4 osmosis in potatoes coursework??
plz help.needs to b dun 4 2moz
plz help.needs to b dun 4 2moz
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Godmaster
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(Original post by tinkabell)
can ne 1 tell me how to work out average percentage change in mass 4 osmosis in potatoes coursework??
plz help.needs to b dun 4 2moz
can ne 1 tell me how to work out average percentage change in mass 4 osmosis in potatoes coursework??
plz help.needs to b dun 4 2moz
use differentiation....lol or u could just work out the mean :-p
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JuniperBlue
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First, find the average change for each concentration (add up and divide by number of tries). Then work out the percentage change for the average:
Change in mass (biggest minus smallest) divided by the original mass, then multiply by 100.
Jo xx
Change in mass (biggest minus smallest) divided by the original mass, then multiply by 100.
Jo xx
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MC
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(Original post by tinkabell)
can ne 1 tell me how to work out average percentage change in mass 4 osmosis in potatoes coursework??
plz help.needs to b dun 4 2moz
can ne 1 tell me how to work out average percentage change in mass 4 osmosis in potatoes coursework??
plz help.needs to b dun 4 2moz
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JuniperBlue
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MC
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tinkabell
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JuniperBlue
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tinkabell
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#9
i cant do it!! can u do the 1st 1 4 me plz so i can c???
Concentration
(M)
1
1
[CENTER]INITIAL
Mass (g)
1.31
1.36
Concentration
(M)
1
1
[CENTER]INITIAL
Mass (g)
1.31
1.36
[/FINAL
Mass (g)
-0.555
-0.521
Mass (g)
-0.555
-0.521
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Tek
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(Original post by JuniperBlue)
To delay or postpone action - putting something off until the last minute!
To delay or postpone action - putting something off until the last minute!
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JuniperBlue
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(Original post by tinkabell)
i cant do it!! can u do the 1st 1 4 me plz so i can c???
Concentration
(M)
1
1
[CENTER]INITIAL
Mass (g)
1.31
1.36
i cant do it!! can u do the 1st 1 4 me plz so i can c???
Concentration
(M)
1
1
[CENTER]INITIAL
Mass (g)
1.31
1.36
[/FINAL
Mass (g)
-0.555
-0.521
Mass (g)
-0.555
-0.521
Average original mass:
1.31 + 1.36 = 2.67
2.67 divided by 2 = 1.335
Average end mass:
0.555 + 0.521 = 1.076
1.076 divided by 2 = 0.538
1.335 - 0.538 = 0.797
0.797 (change) divided by 1.335 (original) = 0.597
0.597 x 100 = average of 59.7% change
Hope this isn't too confusing!
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