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Don Chowdhury
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#1
how do you find the volume of revolution with limits 2 and 0

when f(x) = x(4-x^2)^1/2

anyone?
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Gaz031
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Report 13 years ago
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(Original post by Don Chowdhury)
how do you find the volume of revolution with limits 2 and 0

when f(x) = x(4-x^2)^1/2

anyone?
Is the rotation for y=f(x) about the x axis?
If so, Vol = pi INT [f(x)]^2 dx with limits 2,0
= pi INT x^2(4-x^2) dx
= pi INT 4x^2 - x^4 dx
= pi [(4/3)x^3 - (1/5)x^5] with limits 2,0
= pi [(4/3)(8) - (1/5)(32)]
= pi [32/3 - 32/5]
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