Maths Questions, Please Help People.

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INTEGRATE_ME!!!
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#1
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i am doing some maths homework, and for some reason i am stuck on this question:

Show that:

tanx (cos^2)x
-------------- = 1
sinx cosx

using identities: tan x = (sinx) / (cosx)
and: (cos^2)x + (sin^2)x = 1

i am struggling on this, please help. taa.
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Ralfskini
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#2
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(Original post by INTEGRATE_ME!!!)
i am doing some maths homework, and for some reason i am stuck on this question:

Show that:

tanx (cos^2)x
-------------- = 1
sinx cosx

using identities: tan x = (sinx) / (cosx)
and: (cos^2)x + (sin^2)x = 1

i am struggling on this, please help. taa.
(tanx*cos^2x)/sinxcosx = (sinx/cosx*cos^2x)/sinxcosx =sinxcosx/sinxcosx = 1.
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EDDERS!
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edders
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INTEGRATE_ME!!!
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#4
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(Original post by Ralfskini)
(tanx*cos^2x)/sinxcosx = (sinx/cosx*cos^2x)/sinxcosx =sinxcosx/sinxcosx = 1.
mmm....little confused.

please could you go through it step by step...sorry......
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INTEGRATE_ME!!!
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#5
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(Original post by EDDERS!)
edders
****K OFF WILL YOU, I AM THE ONLY MASKALL..SO ****INGG STOP TRYING TO COPY ME.

YOU ARE SICK IN THE HEAD.

I HATE PEOPLE WHO TRY TO FOLLOW ME.

I AM UNIQUE, SO **** OFF GAYBOY.

YOU ARE NOT MASKALL....I AM.......PISS OFF ****.
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elpaw
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#6
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oooh, a maskall war..... interesting.
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DanielW
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#7
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(tanx(cos^2)x)/(sinxcosx)

= (tanxcosxcosx)/(sinxcosx)

=(tanxcosx)/sinx times cosx/cosx

=(tanxcosx)/sinx times 1

=(tanxcosx)/sinx

=tanx times cosx/sinx

= sinx/cosx times cosx/sinx

=(sinxcosx)/(sinxcosx)

= 1
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INTEGRATE_ME!!!
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(Original post by elpaw)
oooh, a maskall war..... interesting.
ELPAW....PLEASE CUD U HELP ME ON THAT AMTHS QUESTION AMTE, I AM STRUGGLING WITH IT. PLEASE MATE.

YES, THAT GUY IS PRETENDING TO BE REBELLIOUS LIKE ME

I HATE THIS FOLLOWING TREND OF PEOPLE TRYIN TO COPY ME

MASKHOUND, BHAAL85, THIS GUY, AND A FEW OTHERS.

ANYWAYZ, PLEASE CUD U HELP ELPAW...I CANT DO THIS QUESTION BUDDY
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elpaw
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#9
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(Original post by INTEGRATE_ME!!!)
ELPAW....PLEASE CUD U HELP ME ON THAT AMTHS QUESTION AMTE, I AM STRUGGLING WITH IT. PLEASE MATE.

YES, THAT GUY IS PRETENDING TO BE REBELLIOUS LIKE ME

I HATE THIS FOLLOWING TREND OF PEOPLE TRYIN TO COPY ME

MASKHOUND, BHAAL85, THIS GUY, AND A FEW OTHERS.

ANYWAYZ, PLEASE CUD U HELP ELPAW...I CANT DO THIS QUESTION BUDDY
http://users.ox.ac.uk/~chri1957/trig.gif
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INTEGRATE_ME!!!
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#10
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(Original post by elpaw)
http://users.ox.ac.uk/~chri1957/trig.gif
AHHHH.....I SEE........SO THE "DIVIDE BY COS X AND THE MULTIPLY BY COS X WHICH ARE BOTH ON THE NUMERATOR CANCEL EACHOTHER OUT, LEAVING SINX/SINX = 1.......

THANKS BUDDY!!!!!!!! GREAT!!!!!!!

THANKS TO DANIEL ASWELL..........
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INTEGRATE_ME!!!
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#11
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(Original post by INTEGRATE_ME!!!)
AHHHH.....I SEE........SO THE "DIVIDE BY COS X AND THE MULTIPLY BY COS X WHICH ARE BOTH ON THE NUMERATOR CANCEL EACHOTHER OUT, LEAVING SINX/SINX = 1.......

THANKS BUDDY!!!!!!!! GREAT!!!!!!!

THANKS TO DANIEL ASWELL..........
JESUS....THERES ONE MORE TO GO, AND ITS THE HARDEST ONE:

SHOW THAT:

3 + (sin^2)x
------------ = 2 -cosx
2 + cosx

i am having real difficulty with this one. please help!!
i got ahlf way through, then collapsed.....grhjrh.....please guys.
Elpaw the genius to da rescue!!!!!
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INTEGRATE_ME!!!
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#12
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(Original post by INTEGRATE_ME!!!)
JESUS....THERES ONE MORE TO GO, AND ITS THE HARDEST ONE:

SHOW THAT:

3 + (sin^2)x
------------ = 2 -cosx
2 + cosx

i am having real difficulty with this one. please help!!
i got ahlf way through, then collapsed.....grhjrh.....please guys.
Elpaw the genius to da rescue!!!!!
please elpaw!!!!!!!!!!! anyone!
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elpaw
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#13
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#13
(Original post by INTEGRATE_ME!!!)
JESUS....THERES ONE MORE TO GO, AND ITS THE HARDEST ONE:

SHOW THAT:

3 + (sin^2)x
------------ = 2 -cosx
2 + cosx

i am having real difficulty with this one. please help!!
i got ahlf way through, then collapsed.....grhjrh.....please guys.
Elpaw the genius to da rescue!!!!!
(3 + sin²x)/(2+cosx) = (4 - 1 + sin²x)/(2+cosx)
= (4 - (1 - sin²x))/(2+cosx)
= (4 - cos²x)/(2+cosx)
= (2 - cosx)(2+cosx)/(2+cosx)
= 2-cosx
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Pikachu1
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#14
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(Original post by INTEGRATE_ME!!!)
i am doing some maths homework, and for some reason i am stuck on this question:

Show that:

tanx (cos^2)x
-------------- = 1
sinx cosx

using identities: tan x = (sinx) / (cosx)
and: (cos^2)x + (sin^2)x = 1

i am struggling on this, please help. taa.
the solution is:

x2/T(cos)(sine)(1/tan)
x e/abc
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INTEGRATE_ME!!!
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#15
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(Original post by elpaw)
(3 + sin²x)/(2+cosx) = (4 - 1 + sin²x)/(2+cosx)
= (4 - (1 - sin²x))/(2+cosx)
= (4 - cos²x)/(2+cosx)
= (2 - cosx)(2+cosx)/(2+cosx)
= 2-cosx
SORRY! I DONT AHVE A CLUE ABOUT ANY OF THAT....PLEASE CUD U GO THROUGH IT STEP BY STEP......TOO HARD!!!

THANKS MATE.

YOU ARE VERY GOOD AT MATHS!!!
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not1
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#16
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(Original post by INTEGRATE_ME!!!)
i am doing some maths homework, and for some reason i am stuck on this question:
..
i am struggling on this, please help. taa.
maskall, i think you should be able to do that if you want to go to oxford :rolleyes:
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Pikachu1
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#17
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(Original post by edders)
maskall, i think you should be able to do that if you want to go to oxford :rolleyes:
who is Maskall?
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Juwel
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#18
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(Original post by edders)
maskall, i think you should be able to do that if you want to go to oxford :rolleyes:
Too true! He's always posting stuff like this!
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elpaw
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#19
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(Original post by Pikachu1)
who is Maskall?
santa claus
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INTEGRATE_ME!!!
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#20
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(Original post by edders)
maskall, i think you should be able to do that if you want to go to oxford :rolleyes:
THIS QUESTION!!! ITS WELL HARD. I AM REALLY GOOD AT TRIG, I CAN DO ALL THE EXAM QUESTIONS ON TRIGONOMTRY, MUCH HARDER THAN THIS EVEN, BUT I DONT LIKE THESE IDENTITY "SHOW THAT" QUESTIONS. I CANT DO THIS 1.

DO THIS IF I WANNA GO TO OXFORD?
WE HAD A MOCK EXAM FOR P1THE OTHER DAY AND I GOT 86%.
WHICH IS PRETTY GOOD.

I JUST CANT DO THIS QUESTION.

AND ANYWAY, I AM CLEVERER THAN YOU, SO HOW CAN U COMMENT.

COMPARE GCSE GRADES SHALL WE?
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