# **Quick P3 differentiation**Watch

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#1
y = 9^t - 1

dy/dt = ?

0
13 years ago
#2
(Original post by devesh254)
y = 9^t - 1

dy/dt = ?

y+1=9^t
--> ln(y+1)=tln9
y'/y+1=ln9 --> y'=ln9(y+1)
0
#3
(Original post by J.F.N)
y+1=9^t
--> ln(y+1)=tln9
y'/y+1=ln9 --> y'=ln9(y+1)
cheers mate
0
13 years ago
#4
y = 9^t - 1
y = e^ln(9^t) -1
y = e^(t ln9) - 1
dy/dt = ln9 e^[t ln9]
dy/dt = ln9 . e^ln(9^t)
dy/dt = 9^t . ln9
0
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