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i love maths, who else got an A

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Reply 40
Avatar for elpaw
elpaw
15
byb3
Although the binomial distribution is pretty funny.

In what way?
Reply 41
Avatar for kikzen
kikzen
14
Bigcnee
Bath want AAA this year (w/ F.Maths) and AAB (w/o F.Maths), so I hear.


hm well im not sure where i stand really; im doing AS Further Maths (just took it up this year) as well as the other 2 full A Levels
Reply 42
Avatar for theone
theone
Bigcnee
Bath want AAA this year (w/ F.Maths) and AAB (w/o F.Maths), so I hear.


Surely it's the other way around?
theone
Surely it's the other way around?



no because your basicly garanteed an a at maths if you do further so it doesnt count.

love Katy ***
Reply 44
Avatar for yawn1
yawn1
ickle_katy
no because your basicly garanteed an a at maths if you do further so it doesnt count.

love Katy ***

I just had a quick look at Bath website for Maths and it is AAA incl f.Maths or AAB w/o. I think!
Reply 45
Avatar for theone
theone
ickle_katy
no because your basicly garanteed an a at maths if you do further so it doesnt count.

love Katy ***


Ah, but it still looks wierd to me, nevermind :smile:
Reply 46
Avatar for xinxinlu
xinxinlu
math is a fascinating subject. D: though i apply economics, i'd like to change my subject to maths in the second year at university.
Reply 47
Avatar for kikzen
kikzen
14
finally some positivity about maths (degree)
Reply 48
Avatar for Bigcnee
Bigcnee
11
theone
Surely it's the other way around?


Yep. Sorry.
Reply 49
Avatar for Bigcnee
Bigcnee
11
yawn1
I just had a quick look at Bath website for Maths and it is AAA incl f.Maths or AAB w/o. I think!


Correct. I went temporarily dyslexic.
Reply 50
Avatar for Bigcnee
Bigcnee
11
kikzen
finally some positivity about maths (degree)


I would definitely recommend it. It is fairly hard work (ask this question to me again in a few months), and very rewarding.
Quote:
--------------------------------------------------------------------------------
Originally Posted by FurbyMaX
Mathematician, differentiate y=2x^3 with respect to x.

dy/dx = (2 x 3)x^(3-1)
dy/dx = 6x^2

yipeee!!!!!!!!!!
i am a genius!!!!!!!!
Reply 52
Avatar for Juwel
Juwel
18
Oh well done (!) now try y = (4x-3)^2...

As for my modules:
Methods: 93
Pure 1: 80
Discrete 1: 85 (resitting in January)

Taking in January:
Statistics 1, Mechanics 1, Discrete 1

Taking in May/June:
Pure 2, Pure 3, Pure 6, Statistics 2
Reply 53
Avatar for theone
theone
BIG_MASKALL
Quote:
--------------------------------------------------------------------------------
Originally Posted by FurbyMaX
Mathematician, differentiate y=2x^3 with respect to x.

dy/dx = (2 x 3)x^(3-1)
dy/dx = 6x^2

yipeee!!!!!!!!!!
i am a genius!!!!!!!!


No, we meant from first principles :smile:
Integrate (tan(ln{e^x})^1/2 while you're at it.
Reply 55
Avatar for elpaw
elpaw
15
Ralfskini
Integrate (tan(ln{e^x})^1/2 while you're at it.

why the ln(e^x)?
Reply 56
Avatar for kikzen
kikzen
14
ZJuwelH
Oh well done (!) now try y = (4x-3)^2...

As for my modules:
Methods: 93
Pure 1: 80
Discrete 1: 85 (resitting in January)

Taking in January:
Statistics 1, Mechanics 1, Discrete 1

Taking in May/June:
Pure 2, Pure 3, Pure 6, Statistics 2


thats chain rule isnt it?

and what happened to p4 and 5?!
elpaw
why the ln(e^x)?


to confuse.
Reply 58
Avatar for Juwel
Juwel
18
kikzen
thats chain rule isnt it?

and what happened to p4 and 5?!


Chain rule, yes. Nice and easy. I can't stand product rule though...

And I'm doing P6 as part of AS Further Maths, along with M1 and S2. Somehow I don't need to do P4 and P5. Don't ask me I'm a bit tipsy...
Reply 59
Avatar for FurbyMaX
FurbyMaX
BIG_MASKALL
Quote:
--------------------------------------------------------------------------------
Originally Posted by FurbyMaX
Mathematician, differentiate y=2x^3 with respect to x.

dy/dx = (2 x 3)x^(3-1)
dy/dx = 6x^2

yipeee!!!!!!!!!!
i am a genius!!!!!!!!


Maskall, yes you're very good. Now I shall ask you some questions that will test your knowledge on Differentiation.

1) Differentiate y=(7x-4)^4 by first principle.

2) Differentiate y= (((5x+2)^3+6x^2)^1/3)/(9x^3-2)+6x-9*(6x+2)^1/3

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