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    Could some one please do this for me, I am not sure what to do with it, should i just use the chain rule?
    x^2 (4x+1)^.5
    Thanks
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    product rule and chain rule.
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    d/dx x^2 (4x+1)^0.5

    = x^2*2(4x+1)^-0.5 + 2*x(4x+1)^0.5
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    (Original post by droid)
    Could some one please do this for me, I am not sure what to do with it, should i just use the chain rule?
    x^2 (4x+1)^.5
    Thanks
    ok so its first x differential of second plus second x differential of firsta=

    a = x^2
    a` = 2x
    b = (4x+1)^.5
    b` = 1/8(4x+1)^-.5

    dy/dx = ab` + a`b
    = 1/8x^2(4x+1)^-.5 + 2x(4x+1)^.5
 
 
 
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