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TheUnbeliever
Which question, out of curiosity?


A7, A8 and B7
azhao
Some guy I met from Johns punched me when I said I went to a TSR meet.

Like, properly, or as a joke? :confused:

Y__
He was clearly right to do so. Don't you know the first rule of TSR meets? (obscure - well, maybe not so obscure - movie reference inside)

Not obscure (though a good film) and as always, said rule is broken by mentioning it. :yes: For some reason it reminds me of the fictional characters (probably by Pratchett) who can't avoid following signs and could get confused by contradicting ones (anyone know what I'm talking about?).
Reply 3122
alex_hk90
Like, properly, or as a joke? :confused:


Not obscure (though a good film) and as always, said rule is broken by mentioning it. :yes: For some reason it reminds me of the fictional characters (probably by Pratchett) who can't avoid following signs and could get confused by contradicting ones (anyone know what I'm talking about?).


I suppose so, but until someone invents the Virtual Punchator that can punch people over the internet, I feel reasonably safe doing so.
Reply 3123
Y__
From my experience (maths), there are at least one or two questions on every sheet that the vast majority won't be able to answer. Don't know about computer science though.


In my experience, there were often a fair few I couldn't answer:p:

alex_hk90

Not obscure (though a good film) and as always, said rule is broken by mentioning it. :yes: For some reason it reminds me of the fictional characters (probably by Pratchett) who can't avoid following signs and could get confused by contradicting ones (anyone know what I'm talking about?).


I remember them..in the thief of time or something?
ukdragon37
A7, A8 and B7


I don't know anyone who's made any progress on A8 - I handed my answers in earlier tonight without that question. I have no grasp of how to begin it, although the context of the other questions suggests that it might be fairly easy if you spot a trick.

A7 tip: draw a diagram, name the vertices and proceed similarly to A6.

B section I've not looked at.
TheUnbeliever
I don't know anyone who's made any progress on A8 - I handed my answers in earlier tonight without that question. I have no grasp of how to begin it, although the context of the other questions suggests that it might be fairly easy if you spot a trick.

A7 tip: draw a diagram, name the vertices and proceed similarly to A6.

B section I've not looked at.


That's what I did to start with, but I just gave up after it became mildly complicated (it's the flu :frown: )

What questions were you set by the way? For me it was A5 - A9, B3 - B7 and C2-C3
Reply 3126
alex_hk90
Like, properly, or as a joke?


Not obscure (though a good film) and as always, said rule is broken by mentioning it. For some reason it reminds me of the fictional characters (probably by Pratchett) who can't avoid following signs and could get confused by contradicting ones (anyone know what I'm talking about?).
Probably a joke.
ukdragon37
That's what I did to start with, but I just gave up after it became mildly complicated (it's the flu :frown: )


It's a little dull, but fairly straightforward (touch wood - I could easily have been completely wrong!).

What questions were you set by the way? For me it was A5 - A9, B3 - B7 and C2-C3


'A' section until we got stuck.
TheUnbeliever
It's a little dull, but fairly straightforward (touch wood - I could easily have been completely wrong!).



'A' section until we got stuck.


Just realised it's simple if you guess lambda as a half. I was trying to do it without the guess before because wouldn't that not work if the tetrahedron is irregular? :confused:
azhao
Some guy I met from Johns punched me when I said I went to a TSR meet.


Did you ask his username?

The things that had problems with signs are Auditors btw.
alex_hk90
It sure is; which question are you doing - "was there an industrial revolution in the light of new quantitative evidence"?

I'm currently working on the properties of estimators for Econometrics - fun stuff. :rolleyes:


how did you know?! this module is actually unbelievable in its ability to turn me from motivated and ready to work after finishing my maths example sheets to wanting to jump off the top floor of the library lest i have to read about changes in industrial structure again.
ukdragon37
Just realised it's simple if you guess lambda as a half.


Awesome, I was right.

I was trying to do it without the guess before because wouldn't that not work if the tetrahedron is irregular? :confused:


I don't see why not. I solved for the parameter, rather than just guessing it, and I don't remember anything in it which required the triangles to be equilateral.
Reply 3132
why did I sign up for auditioning for the chapel choir again? ****.
Reply 3133
ukebert
Did you ask his username?

The things that had problems with signs are Auditors btw.
I think hes a lurker, he knows aKarma though, thats how he found out about TSR meet.
TheUnbeliever
Awesome, I was right.



I don't see why not. I solved for the parameter, rather than just guessing it, and I don't remember anything in it which required the triangles to be equilateral.


Did you prove the converse for A5 by the way?
ukdragon37
Looking at it again, lambda should be a quarter actually? :confused:


Hm. Say you've got a tetrahedron, ABCD. The lines between the midpoints look like
Unparseable latex formula:

\frac{\mathbf{a}+\mathbf{d}}{2} + \lambda(\frac{\mathbf{b}+\mathbf{c}}{2} - \frac{\mathbf{a}+\mathbf{d}}{2}})

(i.e. the midpoint of AD to the midpoint of BC). Sub in lambda = a half and you get 14(a+b+c+d)\frac{1}{4}(a+b+c+d). Do the same for the other pairs of midpoints and you get the same. No? (I can't find my working copy here, so I'm doing this off the top of my head.)

ukdragon37
Did you prove the converse for A5 by the way?


Hm, I think I forgot actually. Slightly irritating because I'd remembered it earlier, but then got carried away with the algebra and forgot. Alas.
TheUnbeliever
Hm. Say you've got a tetrahedron, ABCD. The lines between the midpoints look like
Unparseable latex formula:

\frac{\mathbf{a}+\mathbf{d}}{2} + \lambda(\frac{\mathbf{b}+\mathbf{c}}{2} - \frac{\mathbf{a}+\mathbf{d}}{2}})

(i.e. the midpoint of AD to the midpoint of BC). Sub in lambda = a half and you get 14(a+b+c+d)\frac{1}{4}(a+b+c+d). Do the same for the other pairs of midpoints and you get the same. No? (I can't find my working copy here, so I'm doing this off the top of my head.)



Hm, I think I forgot actually. Slightly irritating because I'd remembered it earlier, but then got carried away with the algebra and forgot. Alas.


Yes it's a half, sorry. I realised I didn't see the half before the lambda just after I posted (which is why I tried to delete my post :o: )

The converse for A5 is proving to be much harder than the "non-converse". So hard that I still haven't figured out how to do it. Or I could just be missing something obvious.
ukdragon37
Yes it's a half, sorry. I realised I didn't see the half before the lambda just after I posted (which is why I tried to delete my post :o: )


You're clearly not 'with it' because you're normally a far better mathematician than me, from what I remember. :p: In any case, I'm going to call it a night.
TheUnbeliever
You're clearly not 'with it' because you're normally a far better mathematician than me, from what I remember. :p: In any case, I'm going to call it a night.


Again, it's the flu :p:
Tyrotoxism
how did you know?! this module is actually unbelievable in its ability to turn me from motivated and ready to work after finishing my maths example sheets to wanting to jump off the top floor of the library lest i have to read about changes in industrial structure again.

It's a pretty standard first question for the Industrial Revolution topic, as it gives an overview while allowing you to examine some data (Crafts vs Deane and Cole). And that's also a pretty standard response to studying it. :sadnod:

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