log help c2

http://cgi.meikleriggs1.free-online.co.uk/free-online2/mei_papers/

its mei jan 2005 c2 paper

simplify loga(a^2) -4loga(1/a)

????????????????? please help
see the link to see how the Q is written
i couldnt do a small a on loga

[log_a](a^2) - 4[log_a](1/a) = log(a^2)/log(a) - 4log(1/a) / loga
= 2log(a)/log(a) - 4[-log(a)] / log(a)
= 2 log(a)/log(a) + 4log(a)/log(a)
= 6

logaa^2 - 4loga[1/a]
= 2logaa -[-4logaa]
= 2 + 4
= 6

logaa = 1
a^x = a
loga^x = loga
xloga = loga
x = loga/loga = 1

loga(a^2) is same as 2
-4loga(1/a) -> loga((1/a)^-4)) -> loga(a^4) -> 4

is it simplified just 6?

Syncman

loga(a^2) is same as 2
-4loga(1/a) -> loga((1/a)^-4)) -> loga(a^4) -> 4

is it simplified just 6?

El Stevo

thank you!!

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