The Student Room Group
rewrite them as y=2x+1x+2 y = \frac{2x+1}{x+2}

then make x the subject so for this example:

y(x+2)=(2x+1)[br]=>xy+2y=2x+1y(x+2) = (2x+1)[br]=> xy + 2y = 2x +1

bring everything to one side and factorise:

xy+2y2x1=0[br]=>x(y2)+2y1=0xy + 2y - 2x - 1 = 0[br]=> x(y-2) + 2y - 1 =0

can you go from there?
Reply 2
Yep thanku! Problem sorted =D

Latest