The Student Room Group
Reply 1
I don't see why you're talking about derivatives and integrals, as you don't need to use either.

We have, by definition:

sinhx=exex2\sinh x = \dfrac{e^x - e^{-x}}{2}

coshx=ex+ex2\cosh x = \dfrac{e^x + e^{-x}}{2}

tanhx=sinhxcoshx\tanh x = \dfrac{\sinh x}{\cosh x}

sechx=1coshx\mathrm{sech} x = \dfrac{1}{\cosh x}

Use these to prove the identities.
Reply 2
tommm
I don't see why you're talking about derivatives and integrals, as you don't need to use either.

We have, by definition:

sinhx=exex2\sinh x = \dfrac{e^x - e^{-x}}{2}

coshx=ex+ex2\cosh x = \dfrac{e^x + e^{-x}}{2}

tanhx=sinhxcoshx\tanh x = \dfrac{\sinh x}{\cosh x}

sechx=1coshx\mathrm{sech} x = \dfrac{1}{\cosh x}

Use these to prove the identities.


I have heard your decent at maths, just wondering have you studied any AEA maths? How hard did you find it compared to A-level (if you have studied it).
Also would you say it is harder than Step I or even Step II? How similar would it be to them?

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