Wow.
Just did the specimen paper, finished it in time and got 41/50
I got 11, 16, 21, 22, 38, 39, 41, 44 and 48 wrong.
Edit:
Now I'm pretty bad at finding the most efficient/logical ways through problems, and probably even worse at explaining things, but here's what I did:(Original post by PGtips92)
49: No idea!! HELP!!! lol
50: I get 09:20 rather than 09:30 because you want the meat being done last so that means "prepare meat" (10mins) followed by "cook meat" (120mins) followed by "carve meat" (5mins) follwed by "prepare gravy..." (5mins)......... However, you also need to use the oven for the bread FIRST (prior to using it for meat as they want the meat doing last) SO before all of the above, you want to "prepare bread dough" (20mins) followed by "bake bread..." (60mins). The rest can all be done whilst this stuff is in the oven.10+120+5+5+20+60= 220 minutes. 220 minutes before 13:00 is 09:20?!?!?!??!?! Not 09:30?!?! HELP!!!
My reasoning for 49:
For this, I imagined how much you were actually spending with the savings included, compared to what you'd get if there were no savings.
For Make It, you save 5% per £100 spent, compared to Saw Sharp. With Saw Sharp, you save £5 per £100 spent. We therefore know they have the same 'long run' value for money.
Nuts'n Bolts have the same prices as Saw Sharp, but this time you save £6 in £100, which we can easily see is better than Saw Sharp, and since we know Saw Sharp = Make It, we know Nuts'n Bolts are better than both Saw Sharp and Make It.
Trowel Trader are 5% more expensive than Saw Sharp, but you get £10 back. If you bought items worth £100 in 'raw value', it'd cost £105 from Trowel Trader, and £100 from Saw Sharp. You save £10 from Trowel Trader, and £5 from Saw Sharp, which both comes out to £95, so Trowel Trader is equal to Saw Sharp (and hence Make It)
You should easily be able to tell that Plumb It is exactly the same as Trowel Trader, as 10% dearer than Make It = 5% dearer than Saw Sharp.
Therefore, Nuts'n Bolts is the best value for money in the long run.
For 50, you can prepare the bread dough while the meat's in the oven, and after/before you've done the vegetables. I wouldn't be too disheartened by you getting this wrong, as the correct reasoning was there, you just made a tiny mistake.
I probably explained this really badly. Don't worry if you don't understand
Btw, to anyone that both watches the West Wing and did the specimen paper, when reading the extract for question 35, did you instantly think "post hoc ergo propter hoc" before reading the answers? :P
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The Big TSA 2009 Thread watch

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 26102009 22:40
Last edited by Kneechuh; 27102009 at 00:32. 
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 26102009 23:13
hi, I'm new to this forum, just thought I'd help out with question 50
50: I get 09:20 rather than 09:30 because you want the meat being done last so that means "prepare meat" (10mins) followed by "cook meat" (120mins) followed by "carve meat" (5mins) follwed by "prepare gravy..." (5mins)......... However, you also need to use the oven for the bread FIRST (prior to using it for meat as they want the meat doing last) SO before all of the above, you want to "prepare bread dough" (20mins) followed by "bake bread..." (60mins). The rest can all be done whilst this stuff is in the oven.10+120+5+5+20+60= 220 minutes. 220 minutes before 13:00 is 09:20?!?!?!??!?! Not 09:30?!?! HELP!!!
prepare dough  20min
bake  1hr / meanwhile prep veg, boil veg and prep meat
meat in oven  2hr/ set table
carve and prepare gravy  10min
=> 20 + 60 + 120 + 10 = 3h30min
hope that helped :P
EDIT: oh an answer's already been posted above, didnt refresh for a bit nvm then lol sorryLast edited by Tinny113; 26102009 at 23:22. 
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 26102009 23:29
(Original post by Kneechuh)
...(Original post by Tinny113)
... 
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 27102009 07:32
(Original post by rev_pain)
well got an A and B for eng. lit. and language at GCSE but got A* for everything else so english is a weakness 
Merk that Sike of a Mike
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 27102009 10:16
A bit stuck on this q:
1) A cyclist averages 7.5 miles an hour on level ground but only 4.5 miles an hour when going up a hill. If the ratio between flat ground and hills was 1:3, what was the cyclist's average mph over 60 miles?
a) 6mph
b) 5.5 mph
c)5.25 mph
d) 4.75 mph
e) 6.3 mph
I thought i could do this but i got 5mph as my answer which isn't an option lol
Answer:Spoiler:Showc) 5.25 mph 
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 27102009 10:46
Oh and also these ones:
On the M53 is a sign 'Warrington 20'. Just over half a mile further on is another sign
'Warrington 19'. This is not really surprising, since the distances are rounded to the
nearest whole number of miles e.g. numbers of 4.5 and over but less than 5 become 5,
numbers of 4 and over but less than 4.5 become 4. Half a mile futher along the road is a
sign showing 'Warrington 18'.
The distance to Warrington must now be between
A 17.5 miles and 17.6 miles
B 17.6 miles and 18.0 miles
C 18.0 miles and 18.2 miles
D 18.2 miles and 18.4 miles
E 18.4 miles and 18.5 miles
Three lighthouses are visible from the promenade at Rivermouth. One flashes every 1½
minutes, another flashes every 2 minutes, and the third flashes every 50 seconds.
All three have just flashed at the same time.
How long will it be before they all flash at the same time again?
A 6.0 minutes
B 7.5 minutes
C 10.0 minutes
D 30.0 minutes
E 150.0 minutesLast edited by Merk that Sike of a Mike; 27102009 at 11:01. 
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 27102009 11:17
(Original post by Merk that Sike of a Mike)
A bit stuck on this q:
1) A cyclist averages 7.5 miles an hour on level ground but only 4.5 miles an hour when going up a hill. If the ratio between flat ground and hills was 1:3, what was the cyclist's average mph over 60 miles?
a) 6mph
b) 5.5 mph
c)5.25 mph
d) 4.75 mph
e) 6.3 mph
I thought i could do this but i got 5mph as my answer which isn't an option lol
Answer:Spoiler:Showc) 5.25 mph
7.5 + (3*4.5) = 21
then do 21/4 because of the ratio and you get 5.25
but it worries me that that took so long and i dont think i would have got it without knowing the answer :/ only a week left! 
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 27102009 13:05
(Original post by Merk that Sike of a Mike)
A bit stuck on this q:
1) A cyclist averages 7.5 miles an hour on level ground but only 4.5 miles an hour when going up a hill. If the ratio between flat ground and hills was 1:3, what was the cyclist's average mph over 60 miles?
a) 6mph
b) 5.5 mph
c)5.25 mph
d) 4.75 mph
e) 6.3 mph
I thought i could do this but i got 5mph as my answer which isn't an option lol
Answer:Spoiler:Showc) 5.25 mph(Original post by trollman)
...
You want average mph so you need to add up each mph and divide by the number of mph's... if that makes sense.... so...
(15 miles x 7.5 mph) + (45 miles x 4.5 mph)
..........................60................................ ....
= 315 / 60
= 5.25 mph
agreed? 
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 27102009 15:45
(Original post by Merk that Sike of a Mike)
On the M53 is a sign 'Warrington 20'. Just over half a mile further on is another sign
'Warrington 19'. This is not really surprising, since the distances are rounded to the
nearest whole number of miles e.g. numbers of 4.5 and over but less than 5 become 5,
numbers of 4 and over but less than 4.5 become 4. Half a mile futher along the road is a
sign showing 'Warrington 18'.
The distance to Warrington must now be between
A 17.5 miles and 17.6 miles
B 17.6 miles and 18.0 miles
C 18.0 miles and 18.2 miles
D 18.2 miles and 18.4 miles
E 18.4 miles and 18.5 miles
Spoiler:ShowIt's E
18.5 + 1 = 19.5
19.5 rounds up to 20.
(Original post by Merk that Sike of a Mike)
Three lighthouses are visible from the promenade at Rivermouth. One flashes every 1½
minutes, another flashes every 2 minutes, and the third flashes every 50 seconds.
All three have just flashed at the same time.
How long will it be before they all flash at the same time again?
A 6.0 minutes
B 7.5 minutes
C 10.0 minutes
D 30.0 minutes
E 150.0 minutes
Spoiler:ShowIt's E
The prime factors of 90 are: 2 x 3 x 3 x 5
of 120: 2 x 2 x 2 x 3 x 5
50: 2 x 5 x 5
From them, you get 540000, and if you divide that by 3600, you get 150 
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 27102009 16:04
(Original post by Kneechuh)
For this, you can either write out all the times when they flash, and see when you get your first match, but you can also work out the lowest common multiple of the flashes, and this will give you the answer much faster.
Spoiler:ShowIt's E
The prime factors of 90 are: 2 x 3 x 3 x 5
of 120: 2 x 2 x 2 x 3 x 5
50: 2 x 5 x 5
From them, you get 540000, and if you divide that by 3600, you get 150Spoiler:ShowFrom the answer key, D is the answer needed... 
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 27102009 16:11
(Original post by Kneechuh)
For this question, I just worked backwards from the answers. The total distance travelled was 1 mile, and so if you add 1 mile onto the maximum bounds, then you'll see that only one answer can be correct, if the sign said that Warrington was 20 miles away.
Spoiler:ShowIt's E
18.5 + 1 = 19.5
19.5 rounds up to 20.
(Original post by Kneechuh)
For this, you can either write out all the times when they flash, and see when you get your first match, but you can also work out the lowest common multiple of the flashes, and this will give you the answer much faster.
Spoiler:ShowIt's E
The prime factors of 90 are: 2 x 3 x 3 x 5
of 120: 2 x 2 x 2 x 3 x 5
50: 2 x 5 x 5
From them, you get 540000, and if you divide that by 3600, you get 150
There are actually loads of different ways to do this question.
1) You could just write out the multiples for each of them until u get one that matches (which would take ages),
2) you could "backsolve" it which means that you would look at each of the answers and look at them individuall to see if they are multiples of 2 mins, 1 min 30 sec and 50 secs.
Or you could do
3) which is what i did, which is to find the LCM using prime factors.
120 secs can be broken down into (2*2*2*5*3) and 90 secs into (2*5*3*3).
5, 2 and 3 are common so the LCM between these two would be (2*2*2*5*3)*(3)= 360.
Now we just have to find the LCM of 360 and 50.
360 (2*2*2*5*3)*(3) 50 (2*5*5)
2 and 5 are common so answer is: (2*2*2*5*3*3)*(5)= 1800
this is in secs, so 1800/60= 30.
therefore answer is 30 mins.
[Edit: where did u get "divide by 3600" from anyway? i don't really get ur reasoning]Last edited by Merk that Sike of a Mike; 27102009 at 16:16. 
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 27102009 16:18
To salvage myself slightly, I did get that one right when I took the test yesterday 
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 27102009 16:24
(Original post by Kneechuh)
To salvage myself slightly, I did get that one right when I took the test yesterday
Do you get my explanation of it though? 
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 27102009 16:35
(Original post by PGtips92)
Ratio is 1:3 and so because total distance is 60 miles, that means 15 miles uphill and 45 miles downhill.
You want average mph so you need to add up each mph and divide by the number of mph's... if that makes sense.... so...
(15 miles x 7.5 mph) + (45 miles x 4.5 mph)
..........................60................................ ....
= 315 / 60
= 5.25 mph
agreed?
Thank you very much =) 
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 27102009 17:21
(Original post by Merk that Sike of a Mike)
You are right, I still don't really understand the reasoning though.
This is incorrect, and I worked out how to do it anyway just after i posted it lol.
There are actually loads of different ways to do this question.
1) You could just write out the multiples for each of them until u get one that matches (which would take ages),
2) you could "backsolve" it which means that you would look at each of the answers and look at them individuall to see if they are multiples of 2 mins, 1 min 30 sec and 50 secs.
Or you could do
3) which is what i did, which is to find the LCM using prime factors.
120 secs can be broken down into (2*2*2*5*3) and 90 secs into (2*5*3*3).
5, 2 and 3 are common so the LCM between these two would be (2*2*2*5*3)*(3)= 360.
Now we just have to find the LCM of 360 and 50.
360 (2*2*2*5*3)*(3) 50 (2*5*5)
2 and 5 are common so answer is: (2*2*2*5*3*3)*(5)= 1800
this is in secs, so 1800/60= 30.
therefore answer is 30 mins.
[Edit: where did u get "divide by 3600" from anyway? i don't really get ur reasoning] 
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 27102009 18:11
(Original post by Kneechuh)
My reasoning for 49:
For this, I imagined how much you were actually spending with the savings included, compared to what you'd get if there were no savings.
For Make It, you save 5% per £100 spent, compared to Saw Sharp. With Saw Sharp, you save £5 per £100 spent. We therefore know they have the same 'long run' value for money.
Nuts'n Bolts have the same prices as Saw Sharp, but this time you save £6 in £100, which we can easily see is better than Saw Sharp, and since we know Saw Sharp = Make It, we know Nuts'n Bolts are better than both Saw Sharp and Make It.
Trowel Trader are 5% more expensive than Saw Sharp, but you get £10 back. If you bought items worth £100 in 'raw value', it'd cost £105 from Trowel Trader, and £100 from Saw Sharp. You save £10 from Trowel Trader, and £5 from Saw Sharp, which both comes out to £95, so Trowel Trader is equal to Saw Sharp (and hence Make It)
You should easily be able to tell that Plumb It is exactly the same as Trowel Trader, as 10% dearer than Make It = 5% dearer than Saw Sharp.
Set Make It as the "normal" prize or 100%
1) Make It: 100%
2) Saw Sharp: 105% but 5% > 100% // expl.: 5% dearer than (1) but 5% voucher
3) Nuts'n Bolts: 105% but 6% > 99%
4) Trowel Trader: 110% but 10% > 100%
5) Plumb It: 110% but 10% > 100%
edit: quotefix 
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 28102009 14:02
Still don't get these two questions:
1)On the M53 is a sign 'Warrington 20'. Just over half a mile further on is another sign
'Warrington 19'. This is not really surprising, since the distances are rounded to the
nearest whole number of miles e.g. numbers of 4.5 and over but less than 5 become 5,
numbers of 4 and over but less than 4.5 become 4. Half a mile futher along the road is a
sign showing 'Warrington 18'.
The distance to Warrington must now be between
A 17.5 miles and 17.6 miles
B 17.6 miles and 18.0 miles
C 18.0 miles and 18.2 miles
D 18.2 miles and 18.4 miles
E 18.4 miles and 18.5 miles
2) The cog sizes and chain length on a bicycle are designed to even out wear, so that the same
hole in the chain does not encounter the same tooth on the cog in every revolution. The chain
wheel (front cog) of a particular bicycle has 48 teeth, the rear cog has 18 teeth and the chain has
90 holes.
How many revolutions must the front cog do before the chain and both cogs are back in exactly
the same relative positions (i.e. the same holes are encountering the same teeth on both cogs)?
A 5
B 8
C 15
D 20
E 30 
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 28102009 14:16
(Original post by Merk that Sike of a Mike)
Still don't get these two questions:
1)On the M53 is a sign 'Warrington 20'. Just over half a mile further on is another sign
'Warrington 19'. This is not really surprising, since the distances are rounded to the
nearest whole number of miles e.g. numbers of 4.5 and over but less than 5 become 5,
numbers of 4 and over but less than 4.5 become 4. Half a mile futher along the road is a
sign showing 'Warrington 18'.
The distance to Warrington must now be between
A 17.5 miles and 17.6 miles
B 17.6 miles and 18.0 miles
C 18.0 miles and 18.2 miles
D 18.2 miles and 18.4 miles
E 18.4 miles and 18.5 miles
(Original post by Merk that Sike of a Mike)
2) The cog sizes and chain length on a bicycle are designed to even out wear, so that the same
hole in the chain does not encounter the same tooth on the cog in every revolution. The chain
wheel (front cog) of a particular bicycle has 48 teeth, the rear cog has 18 teeth and the chain has
90 holes.
How many revolutions must the front cog do before the chain and both cogs are back in exactly
the same relative positions (i.e. the same holes are encountering the same teeth on both cogs)?
A 5
B 8
C 15
D 20
E 30 
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 28102009 14:36
i got a letter from my college today saying thanks for the app! but now im getting even more worried about the TSA essay section does anyone have any essays they have written that i could take a look at? i am yet to write a practice one i just want to see the kind of length/structure that we could get in 30 minutes!

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 28102009 17:28
Hi guys. Only just started my TSA practice, but I literally cannot get the answer to Number 18 on the Specimen Paper... i'm so confused!
'The island Republic of Outlandia has three banks; Barkers, Floyds and national. During a particular day Barkers customers have written cheques worth three millions Lire to Floyds customers and cheques worth four million Lira to National Customers. Floyds customers have written chequres worth four million lire to barkers customers and cheques worth five million Lire to National customers. National customers have written cheques worth three million Lira to Barkers customers and cheques worth two million Lire to Floyds customers.
The Banks could settle all the debts to each other that arise because of tehse cheques by:
A) Floyds Bank paying one million Lira to Barkers Bank and Barkers Bank paying one million Lira to national bank
B) Floyds bank paying three million Lira to National Bank
c) Floyds Bank paying four million Lira to National Bank
D) Barkers Bank paying one million Lira to National Bank
E) Barkers Bank paying four million Lira to National Bank
Any explanation would be fantastic.
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