Hey there! Sign in to join this conversationNew here? Join for free

The Soc for People of 'GRDCT2008' Mk VI Watch

    Offline

    2
    ReputationRep:
    (Original post by ArchedEdge)
    Had my 18th last night....dear god I think I may still be drunk lol
    :yy: was good then!?
    Offline

    0
    ReputationRep:
    (Original post by raceforthefishman)
    :yy: was good then!?
    Yeahhh was great
    Offline

    2
    ReputationRep:
    How do I find out when the oxford interviews for biochemistry are???
    Offline

    12
    ReputationRep:
    (Original post by raceforthefishman)
    How do I find out when the oxford interviews for biochemistry are???
    Check your college/subject website. According to some people at my school, Oxford published the dates in a few subjects quite a while back. I've no idea how true any of that is though.
    Offline

    16
    (Original post by jaz_jaz)
    WTF, CS you just sent it off and you have an acknowledgement?
    Also got one from UCL this morning...
    Offline

    2
    ReputationRep:
    (Original post by GHOSH-5)
    Check your college/subject website. According to some people at my school, Oxford published the dates in a few subjects quite a while back. I've no idea how true any of that is though.
    :awesome: thanks



    ...theyre not going to ask me to go :sigh:

    Do you fancy doing some maths??
    Offline

    12
    ReputationRep:
    (Original post by raceforthefishman)
    ...theyre not going to ask me to go :sigh:

    Do you fancy doing some maths??
    I bet they will :yep:

    Hit me.
    Offline

    2
    ReputationRep:
    (Original post by GHOSH-5)
    I bet they will :yep:

    Hit me.
    ....
    How would I go about differentiating
    ln(x(x+1)) ??

    This entire section on e's and lns is not fun
    Offline

    12
    ReputationRep:
    (Original post by raceforthefishman)
    ....
    How would I go about differentiating
    ln(x(x+1)) ??

    This entire section on e's and lns is not fun
     \ln x(x+1) = \ln x + \ln (x+1) , and you should know that, for some function f(x),  \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln f(x)) = \dfrac{f'(x)}{f(x)} ; apply this fact to each of the two terms.
    Offline

    0
    ReputationRep:
    Wait, I thought acknowledgment meant they've got it, its not a rejection right now but they're considering it.
    Cuz I got an email from York the day after saying your application has been recieved and acknowledged :confused:
    Offline

    0
    ReputationRep:
    (Original post by ArchedEdge)
    Had my 18th last night....dear god I think I may still be drunk lol
    This is great haha!
    Had my mates 18th last night; was weak. Mine's tonighttt :woo:
    Offline

    2
    ReputationRep:
    (Original post by GHOSH-5)
     \ln x(x+1) = \ln x + \ln (x+1) , and you should know that, for some function f(x),  \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln f(x)) = \dfrac{f'(x)}{f(x)} ; apply this fact to each of the two terms.
    aaaaah
    separate them!!
    Thanks

    ln1/(3x+1)

    Seperate them again or not??

    Modulus function fun now :awesome:
    Offline

    0
    ReputationRep:
    (Original post by jaz_jaz)
    This is great haha!
    Had my mates 18th last night; was weak. Mine's tonighttt :woo:
    Ahhh enjoy it!

    I don't think it's possible to not enjoy your own 18th, unless something goes seriously wrong :p:
    Offline

    2
    ReputationRep:
    (Original post by jaz_jaz)
    Wait, I thought acknowledgment meant they've got it, its not a rejection right now but they're considering it.
    Cuz I got an email from York the day after saying your application has been recieved and acknowledged :confused:
    I got my offer through ucas from manchester..
    thn shortly recieved an email from them saying 'we have recieved you're application, it is being considered and we may invite you to interview' .....little bit late I feel

    Have a good one tonight
    Offline

    3
    ReputationRep:
    (Original post by GHOSH-5)
     \ln x(x+1) = \ln x + \ln (x+1) , and you should know that, for some function f(x),  \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln f(x)) = \dfrac{f'(x)}{f(x)} ; apply this fact to each of the two terms.
    Cheers for the rep
    Offline

    12
    ReputationRep:
    (Original post by raceforthefishman)
    aaaaah
    separate them!!
    Thanks

    ln1/(3x+1)

    Seperate them again or not??

    Modulus function fun now :awesome:
    Is this:  \ln \dfrac{1}{3x+1} ?

    Separate indeed! :smile:
    Offline

    12
    ReputationRep:
    (Original post by bob9001)
    Cheers for the rep
    Offline

    0
    ReputationRep:
    (Original post by GHOSH-5)
     \ln x(x+1) = \ln x + \ln (x+1) , and you should know that, for some function f(x),  \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln f(x)) = \dfrac{f'(x)}{f(x)} ; apply this fact to each of the two terms.
    Be a nice man and do the rest of it for me please? :o:
    Offline

    12
    ReputationRep:
    (Original post by ArchedEdge)
    Be a nice man and do the rest of it for me please? :o:
     \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln x(x+1)) = \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln x + \ln (x+1)) = \dfrac{1}{x} + \dfrac{1}{x+1}
    Offline

    2
    ReputationRep:
    mathtastic!

    hellooo
 
 
 
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Updated: April 8, 2010
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • Poll
    Brexit voters: Do you stand by your vote?
    Useful resources
    AtCTs

    Ask the Community Team

    Got a question about the site content or our moderation? Ask here.

    Welcome Lounge

    Welcome Lounge

    We're a friendly bunch. Post here if you're new to TSR.

    Groups associated with this forum:

    View associated groups
  • See more of what you like on The Student Room

    You can personalise what you see on TSR. Tell us a little about yourself to get started.

  • The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

    Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

    Write a reply...
    Reply
    Hide
    Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.