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The Soc for People of 'GRDCT2008' Mk VI Watch

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    (Original post by jaz_jaz)
    Wait, I thought acknowledgment meant they've got it, its not a rejection right now but they're considering it.
    Cuz I got an email from York the day after saying your application has been recieved and acknowledged :confused:
    Yeah, an acknowledgement is when they say 'just to let you know, we've got your application, and will give you more info later (i.e. offer/interview/rejection).
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    (Original post by GHOSH-5)
     \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln x(x+1)) = \dfrac{\mathrm{d}}{\mathrm{d}x} (\ln x + \ln (x+1)) = \dfrac{1}{x} + \dfrac{1}{x+1}

    Omg that was ridiculously easy wasn't it?

    I'm such a muppet at maths
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    (Original post by raceforthefishman)
    How do I find out when the oxford interviews for biochemistry are???
    http://www.ox.ac.uk/admissions/under...timetable.html

    14th-15th Dec for all and 14th-16th for some apparently
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    (Original post by GHOSH-5)
    Is this:  \ln \dfrac{1}{3x+1} ?

    Separate indeed! :smile:
    Yes it was that!!

    so Id get ln1-ln(3x+1)

    ln1 would disappear magically
    so then
    -3/(3x+1)
    :awesome:

    *sorry about the lack of latex*

    (Original post by John Locke)
    14th-15th Dec for all and 14th-16th for some apparently
    Thanks!
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    (Original post by raceforthefishman)
    Yes it was that!!

    so Id get ln1-ln(3x+1)

    ln1 would disappear magically
    so then
    -3/(3x+1)
    :awesome:
    All correct. :smile:
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    OHHHHHHHHHHHHHHHH
    I have 4/5 acknowledgements then
    Erghh, lack of tubes and weather = postponed til a later date.
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    Ghosh, help me!

    How does one integrate 2sintcos^2t ?
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    (Original post by ArchedEdge)
    Ghosh, help me!

    How does one integrate 2sintcos^2t ?
    He's not online at the mo'
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    (Original post by Champagne Supernova)
    He's not online at the mo'
    Damn that boy!
    He'll do it sooner or later anyways
    and I'm in no rush
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    (Original post by ArchedEdge)
    Ghosh, help me!

    How does one integrate 2sintcos^2t ?
    Make the orgasmic substitution of  u = \cos t .
    Spoiler:
    Show
     I = \displaystyle\int 2\sin t \cos^2 t \ \mathrm{d}t

     u = \cos t \implies \mathrm{d}u = -\sin t \mathrm{d}t \implies \mathrm{d}t = \dfrac{\mathrm{d}u}{-\sin t}

    Shoving everything we already have in our integral:

     I = \displaystyle\int 2\sin t \ u^2 \ \dfrac{\mathrm{d}u}{-\sin t} = \displaystyle\int -2u^2 \ \mathrm{d}u

    I expect some rep in return for helping you :awesome:
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    (Original post by GHOSH-5)
    Make the orgasmic substitution of  u = \cos t .
    Spoiler:
    Show
     I = \displaystyle\int 2\sin t \cos^2 t \ \mathrm{d}t

     u = \cos t \implies \mathrm{d}u = -\sin t \mathrm{d}t \implies \mathrm{d}t = \dfrac{\mathrm{d}u}{-\sin t}

    Shoving everything we already have in our integral:

     I = \displaystyle\int 2\sin t \ u^2 \ \dfrac{\mathrm{d}u}{-\sin t} = \displaystyle\int -2u^2 \ \mathrm{d}u

    I expect some rep in return for helping you :awesome:
    Say what???
    I'll look forward to this topic :sigh:
    Is it in c4??????
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    :zomg:
    bloody core 3.
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    Great...got that to look forward to. :indiff:
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    (Original post by raceforthefishman)
    Say what???
    I'll look forward to this topic :sigh:
    Is it in c4??????
    It is C4 - integration by substitution. It's 'sort of' the integral analogue of chain rule; ArchedEdge's integral is in fact a very clear example of 'inverse chain rule', but integration by substitution is not always the opposite of chain rule.
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    Oh joy. As if C3 and FP1 weren't bad enough, FP2 and C4 to come :shoot:
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    (Original post by GHOSH-5)
    It is C4 - integration by substitution. It's 'sort of' the integral analogue of chain rule; ArchedEdge's integral is in fact a very clear example of 'inverse chain rule', but integration by substitution is not always the opposite of chain rule.
    ^^ :dry:

    I don't know whether I remembered to say thank you for letting me use your maths brain...so if I didn't, thank you!
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    (Original post by raceforthefishman)
    ^^ :dry:

    I don't know whether I remembered to say thank you for letting me use your maths brain...so if I didn't, thank you!
    You're welcome

    edit: Cheers for being a rep-slave ArchedEdge :awesome:
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    Ghoshhh, would you be able to explain the method to find the domain and range of functions.
    I've asked literally every person I know and you're my last hope! :o:
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    Southampton acknowledgement.
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    (Original post by Champagne Supernova)
    Southampton acknowledgement.
    :woo:

    Good news! St John's have said that if I'm called for interview, it'll be on the morning of 12th December, so I can just get a later flight to my ski trip
 
 
 
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