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The Soc for People of 'GRDCT2008' Mk VI Watch

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    (Original post by GHOSH-5)
    Does there exist a number x such that both cosx = -1 and sinx = 1?

    Archededge: there are various ways to do it, such as calculus. Alternatively, write 12cosx - 4sinx in the form Rcos(x+a), where R and a are constants to be found. Hence the minimum of 12cosx - 4sinx will be the minimum of Rcos(x+a) which is -R, and this occurs for x+a = pi.

    In my world, yes.....I can also divide by 0 without terrible consequences
    *Thats probably where my C3 went wrong today*
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    (Original post by jaz_jaz)
    yup resit tomorrow!
    going through my textbook now lol.
    terrified of unit 3 though! I find it SO hard!
    OMG i know right?!
    Srsly they could have warned us.
    That's what made me decide on the retake!

    eek eek. I have to do it in the morning too cos of stupid stats :|
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    (Original post by raceforthefishman)
    In my world, yes.....I can also divide by 0 without terrible consequences
    You'll go to Hell for that.
    Spoiler:
    Show
    :awesome:
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    :rofl: Ghosh
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    (Original post by GHOSH-5)
    You'll go to Hell for that.
    Spoiler:
    Show
    :awesome:
    What is is not to be a mathematician :rolleyes:

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    D1 - worst. module. everrrr.
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    (Original post by John Locke)
    D1 - worst. module. everrrr.
    Exam today?
    Or just general nastiness?
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    (Original post by raceforthefishman)
    Exam today?
    Or just general nastiness?
    nah, the exams on friday. it's pretty woeful in general as well.

    i spend 15mins trying to understand where i went wrong on a question, only to eventually realise that i had got it right in the first place. hate my life.
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    I still don't understand why something x 0 = 0
    never have
    never will
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    (Original post by lozz2601)
    I still don't understand why something x 0 = 0
    never have
    never will
    Because if you have something 0 times then you have 0

    Like 5 x 2 is saying you have two 5s added together
    and 3 x 4 is three 4s added together

    well if you had 5 x 0 you have no fives added together and hence nothing

    :yy:
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    (Original post by raceforthefishman)
    Because if you have something 0 times then you have 0

    Like 5 x 2 is saying you have two 5s added together
    and 3 x 4 is three 4s added together

    well if you had 5 x 0 you have no fives added together and hence nothing

    :yy:
    But
    you already HAVE the five
    like if you have five sweets and you x by zero
    you don't multiply them by anything
    so they stay the same!!
    (i know its wrong mathematically i just dont think it makes common sense sense :p:)
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    (Original post by lozz2601)
    I still don't understand why something x 0 = 0
    never have
    never will
    Sketchy proof from axioms:

    1 = 1 and hence 1 - 1 = 0. a = a and hence a - a = 0.

    But a - a = a(1 - 1) = a0. Hence a0 = 0.
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    (Original post by lozz2601)
    But
    you already HAVE the five
    like if you have five sweets and you x by zero
    you don't multiply them by anything
    so they stay the same!!
    (i know its wrong mathematically i just dont think it makes common sense sense :p:)
    Well its like you've got 5 there fair enough...but then you've got 5 no times over...so overall you have nothing

    I can see the confusion...I wasn't sure with dividing by 0 for a very long time


    5(now you see it) x 0 (oh noes) = 0 (it disappeared)
    :awesome:
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    (Original post by raceforthefishman)
    Well its like you've got 5 there fair enough...but then you've got 5 no times over...so overall you have nothing

    I can see the confusion...I wasn't sure with dividing by 0 for a very long time


    5(now you see it) x 0 (oh noes) = 0 (it disappeared)
    :awesome:
    I thought you were a scientist, even I noes things don't disappear
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    (Original post by lozz2601)
    I thought you were a scientist, even I noes things don't disappear
    :shh: Its magic
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    URGHHH
    tyre puncture
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    :dice:
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    (Original post by GHOSH-5)
    Sketchy proof from axioms:

    1 = 1 and hence 1 - 1 = 0. a = a and hence a - a = 0.

    But a - a = a(1 - 1) = a0. Hence a0 = 0.
    this proof is nice i understand it :yep:
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    (Original post by overclocked)
    URGHHH
    tyre puncture
    Oh no :console:
    Thats not going to be cheap for a new tyre :sad:
    I need a new spare atm
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    :e
 
 
 
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