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# The Soc for People of 'GRDCT2008' Mk VI watch

1. Ahaha Cs!! oh **** you capitals
2. (Original post by GHOSH-5)
Yes. I came so much, the closet overflowed
...I see what you did there....
3. This thread just made a turn for the worse, and I wasn't even involved.

4. (Original post by ArchedEdge)
This thread just made a turn for the worse, and I wasn't even involved.

Even worse now you're here
5. (Original post by GHOSH-5)
Even worse now you're here
To think, you may be practically neighbours in September
6. (Original post by natty_d)
To think, you may be practically neighbours in September
Not quite. He'll be a 5 minute walk down the road, and I might not be there (******* STEP).
7. (Original post by GHOSH-5)
Not quite. He'll be a 5 minute walk down the road, and I might not be there (******* STEP).
I have every faith you'll do well, Ghosh

But I did put 'may be' in there
8. (Original post by natty_d)
I have every faith you'll do well, Ghosh

But I did put 'may be' in there

Fair point.
9. (Original post by GHOSH-5)
Even worse now you're here
Hai bbz

10. Ghosh help me bro.

Stuck on C, how you find the area of the parallelogram.

And then how to approach D.

Attached Images

11. (Original post by ArchedEdge)
Ghosh help me bro.

Stuck on C, how you find the area of the parallelogram.

And then how to approach D.

c) Consider the first quadrant: Let the tangent to the ellipse in the first quadrant be called L. It has equation . Let Y be the point where L meets the y-axis and X be the point where L meets the x-axis. You can find the coordinates of X and Y quite easily. Hence what is the area of triangle XYO (O is the origin)? Hence what is the area of the whole parallelogram?
Spoiler:
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and .
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.
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, due to symmetry.
d) The area of the two types of wood are equal iff half of the area of the parallelogram = the area in the parallelogram but surrounding the ellipse.

Hence we need to solve:

.
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I think that , but I haven't got a pen and paper at hand to check.

edit: cheers Natty
12. (Original post by GHOSH-5)
c) Consider the first quadrant: Let the tangent to the ellipse in the first quadrant be called L. It has equation . Let Y be the point where L meets the y-axis and X be the point where L meets the x-axis. You can find the coordinates of X and Y quite easily. Hence what is the area of triangle XYO (O is the origin)? Hence what is the area of the whole parallelogram?
Spoiler:
Show
and .
Spoiler:
Show
.
Spoiler:
Show
, due to symmetry.
d) The area of the two types of wood are equal iff half of the area of the parallelogram = the area in the parallelogram but surrounding the ellipse.

Hence we need to solve:

.
Spoiler:
Show
I think that , but I haven't got a pen and paper at hand to check.

edit: cheers Natty
Ahhh yes I forgot about the equation thing they gave you earlier.

And I just got a lil confused about the wording of the last question
13. On hold at Manchester Med school, what a bunch of gays.
14. How rude of them!
15. I feel for you
16. (Original post by v1oXx-)
On hold at Manchester Med school, what a bunch of gays.
Sorry to hear that but, you're better off at Barts tbh. Don't come to Manchester!
17. I need to have a complete sort out of all my folders
18. BBB from Warwick...
19. (Original post by Champagne Supernova)
BBB from Warwick...
win! congratsss!

for anyone that might know; RE: the ucas deadline thing that was extended to 22nd Jan, does this mean i could still add a choice on track for equal consideration? or is it only for schools that had snow issues and specifically requested a deadline extension (which im not sure if ours did )? infact, does it even apply for peoples forms that have already been processed?
20. (Original post by John Locke)
win! congratsss!

for anyone that might know; RE: the ucas deadline thing that was extended to 22nd Jan, does this mean i could still add a choice on track for equal consideration? or is it only for schools that had snow issues and specifically requested a deadline extension (which im not sure if ours did )? infact, does it even apply for peoples forms that have already been processed?

I think it's applicable for all scenarios. The UCAS site doesn't give much info, and if the UCAS/Apps forum can't provide an answer, then phone UCAS?

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