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    PCl5 <---> PCl3 + Cl2

    1.68 moles of PCl5 mixed with 0.36 moles PCl3 in a container of volume 2 DM^3. 1.44 moles PCl5 remained at equilibirum.

    What is Equilibrium constant?

    please help and show workings if u can =D
    Thanks in advanced =DD
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    Is this Kc or Kp?

    are they all gases?
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    yes all gases and its Kc
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    Okay so we start with moles:

    PCl5 = 1.68
    PCl3 = 0.36
    Cl2 = 0

    At equilibrium:

    PCl5 = 1.44
    PCl3 = 0.36 + (1.68-1.44) = 0.6
    Cl2 = (1.68-1.44) = 0.24

    Using the volume of 2 dm3 input these values into the expression for Kc = [PCl3][Cl2]/[PCl5]

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    (Original post by EierVonSatan)
    Okay so we start with moles:

    PCl5 = 1.68
    PCl3 = 0.36
    Cl2 = 0

    At equilibrium:

    PCl5 = 1.44
    PCl3 = 0.36 + (1.68-1.44) = 0.6
    Cl2 = (1.68-1.44) = 0.24

    Using the volume of 2 dm3 input these values into the expression for Kc = [PCl3][Cl2]/[PCl5]

    Ah cheers
 
 
 
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