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Trigonometric Identities watch

1. Hi, I need some help with this...

Prove that:
1 + [1 / tan^2 A]

is equal to

1 / [sin^2 A]

I hope that makes sense. The / means divide and ^2 means to the power of 2 obviously.

Thanks!
2. Write 1 as tan^2 A / tan^2 A.
3. The way to learn these is to mess about a lot , getting them wrong even, and trying different things, until you see what sort of methods work.
4. (Original post by generalebriety)
Write 1 as tan^2 A / tan^2 A.
Is it not better to write the 1 as Sin^2 / Sin^2 ?
5. (Original post by generalebriety)
Write 1 as tan^2 A / tan^2 A.
Then what?
6. (Original post by Narik)
Then what?
Your thread title is "trigonometric identities". Why don't you try using a trigonometric identity?
7. (Original post by stevencarrwork)
Is it not better to write the 1 as Sin^2 / Sin^2 ?
Well, maybe (though I don't really know what you mean by "better" other than that the identities involved are more well known), but it's a lot less obvious. There's no point in giving a method that people would never spot in the exam.
8. (Original post by generalebriety)
Your thread title is "trigonometric identities". Why don't you try using a trigonometric identity?
Tan = sin/ cos is one identity.

Sin^2 + Cos^2 is another.

Bash them in and see what happens.
9. (Original post by stevencarrwork)
Tan = sin/ cos is one identity.

Sin^2 + Cos^2 is another.

Bash them in and see what happens.
I think you need to read the posting guidelines. I know how to do the problem, and so do you; I was trying to lead the OP towards finding their own solution, not to hand it to them on a plate.
10. (Original post by generalebriety)
I think you need to read the posting guidelines. I know how to do the problem, and so do you; I was trying to lead the OP towards finding their own solution, not to hand it to them on a plate.
Plate please!
11. (Original post by Narik)
Plate please!
Sounds like you need to read the posting guidelines too.
12. (Original post by Narik)
Plate please!
Try substitution, see if that works. I doubt anyone will give it you on a plate; otherwise you'll be straight back here as soon as you see another one of the same question.

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