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    Prove that:

    2 + tan^2Ɵ + [ 1 / tan^2Ɵ]

    is equal to:

    1 / (sin^2Ɵ cos^2Ɵ)

    • Thread Starter
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    The &#415 thing is 'Ɵ'
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    Whenever you get asked about trig identities the most brainless way to go around doing it is to express everything in terms of sin and cos and then express everything with a common denominator.

    Often there are quicker, more subtle methods, but if you're really stuck do the above.
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    I should have read the title more carefully. I was expecting a story telling us the real ID of The Stig
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    (Original post by Chewwy)
    it isn't.
    I believe it is.

    I used the brainless method of putting everything over a common denominator, and factorising.
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    (Original post by Chewwy)
    it isn't.
    The two expressions are equal .

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    I think ive got it- who knows though- i havent properly done these trig identities yet

     1/(sin^2 x cos^2 x)



(sec^2 x)(cosec^2 x)



(1+ tan^2 x)(cosec^2 x)



(1+ tan^2 x)(1+ cot^2 x)



(1+ tan^2 x)(1+ 1/tan^2 x)



1+ 1/tan^2 x +tan^2 x +1



2 + tan^2 x + 1/tan^2 x

    tadaaaa!!
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    who is going around the maths forum deleting posts?

    i'm assuming it's dave.
 
 
 
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Updated: July 19, 2009
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