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    • Thread Starter
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    here we go again :p:
    integrate the following with respect to x

    y=4+x4+√x

    ∫ (4 + x4 +
    i get to there and get lost in what i'm meant to be doing

    i get say
    y= x8
    ∫x8 dx
    = x9 /9 + C
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    Community Assistant
    Write \sqrt{x} as x^{\frac{1}{2}}.
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    so would it go
    ∫ (4 + x4 +x1/2 )dx
    ∫ (4 + x-4 +x1/2 )dx



    and then i become confused on the most of it
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    (Original post by robinson999)
    so would it go
    ∫ (4 + x4 +x1/2 )dx
    ∫ (4 + x-4 +x1/2 )dx
    Where have you got the -4 from?

    When you integrate, you raise the power by 1 and divide by the new power. So, for example, \displaystyle \int x^4\ \mbox{d}x = \dfrac{x^5}{5} + C. Remember that \displaystyle \int (4 + x^4 + \sqrt{x})\ \mbox{d}x = \int 4\ \mbox{d}x + \int x^4\ \mbox{d}x + \int x^{1/2}\ \mbox{d}x.
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    Remember you add a power and divide by the new power when integrating.
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    The first one of your two offerings.

    Follow the rule:

    Add 1 to the power and divide by the new power (Add one more, drop it through the trap door).

    Work along from left to right one term at a time.

    Don't forget the constant of integration.
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    (Original post by nuodai)
    Where have you got the -4 from?

    When you integrate, you raise the power by 1 and divide by the new power. So, for example, \displaystyle \int x^4\ \mbox{d}x = \dfrac{x^5}{5} + C.
    i dunno, i trying to go by, it seems failed lecture notes :p:

    that just confuses me
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    Then you need to go right back to the beginning of integration. PM me with an email address and I will send you a powerpoint or two to explain it.
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    cheers , sorry this take some time not a maths student, but my uni think its important to do on my degree
    sort of getting it from the post
 
 
 
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