Find the integral of:
Top heavy so I use the table method to divide through and find remainders:
I get x with remainder -3x^2 and -2x....
So I have A(x+2) + B(x+1) = -3x^2 -2x..
With a bit of magic I get:
-1/(x+1) + 8(x+2) and x
0.5x^2 − ln |x + 1| + 8ln|x + 2| + c.
But apparently the answer is this and -3x...Where does the -3x come from?
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- Thread Starter
- 27-07-2009 14:55
- 27-07-2009 15:18
Your "remainder" is wrong. You can divide (x+1)(x+2) into -3x^2 to get a smaller remainder.
- 27-07-2009 15:30
For checking purposes may I recommend..