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furthermaths mechanics projectile~~ OBLIQUE IMPACT WITH A FIXED SURFACE NOTE? Watch

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    arrr.. omg..

    i dont understand what my lecturer was teaching about..

    here is the pdf format note from her...
    can anyone explain??
    i understand v=eusin30 .. but i dunno the solution of the example//

    ....V= 5(10sin60) = 5/4 (square root 3)
    how to get this??

    i will be killed because next week is the test for this...

    helphelphelp~~!!:yes: :woo:
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  1. File Type: pdf Lesson%206%20Impact%20with%20a%20Fixed%20Surface%20presentation.pdf (190.1 KB, 734 views)
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    (Original post by tsrhow)
    arrr.. omg..

    i dont understand what my lecturer was teaching about..

    here is the pdf format note from her...
    can anyone explain??
    i understand v=eusin30 .. but i dunno the solution of the example//

    ....V= 5(10sin60) = 5/4 (square root 3)
    how to get this??

    i will be killed because next week is the test for this...

    helphelphelp~~!!:yes: :woo:
    You're not really giving me alot to go on.

    What don't you understand, if you put 5(10sin60) in a calc you will get 5/4 (square root 3) if thats the bit you dont understand?

    All you are doing is splitting the example into parallel and perpend. to the wall and then using the formula's above.
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    (Original post by The Muon)
    You're not really giving me alot to go on.

    What don't you understand, if you put 5(10sin60) in a calc you will get 5/4 (square root 3) if thats the bit you dont understand?

    All you are doing is splitting the example into parallel and perpend. to the wall and then using the formula's above.

    sorry, 5/4=1.25

    square root 3= 1.73..

    multiply 1.25 with 1.73=2.16..

    but,10sin60=8.66...

    8.66..... times 5=43.3 ! why is it??
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    Looking into it with my thinking hat on it shouldn't be 5(10sin60), it should be 0.5 x 0.25 (10sin60) - from the equation a little higher
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    ya!!!

    (10sin60) this is rite and equal to 5times squareroot3

    BUT HOW COME GOT A 5 BEFORE 1OSIN60

    AND A 1OVER 4 BEFORE 5TIMES SQUAREROOT3??
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    (Original post by The Muon)
    Looking into it with my thinking hat on it shouldn't be 5(10sin60), it should be 0.5 x 0.25 (10sin60) - from the equation a little higher


    ya!!!

    (10sin60) this is rite and equal to 5times squareroot3

    BUT HOW COME GOT A 5 BEFORE 1OSIN60

    AND A 1OVER 4 BEFORE 5TIMES SQUAREROOT3??
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    (Original post by tsrhow)
    ya!!!

    (10sin60) this is rite and equal to 5times squareroot3

    BUT HOW COME GOT A 5 BEFORE 1OSIN60

    AND A 1OVER 4 BEFORE 5TIMES SQUAREROOT3??

    It's a misprint. The 5 in front of the brackets shouldn't be there.

    The velocity perpendicular to the wall before impact is 10\sin 60

    and after impact it is \frac{1}{4}\times 10\sin 60 = \frac{5}{4}\sqrt{3}
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    (Original post by ghostwalker)
    It's a misprint. The 5 in front of the brackets shouldn't be there.

    The velocity perpendicular to the wall before impact is 10\sin 60

    and after impact it is \frac{1}{4}\times 10\sin 60 = \frac{5}{4}\sqrt{3}

    thanks!! hope this help!!! tq veryvery much

    i hate misprint
 
 
 
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