# natural log

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#1
ok i know this will be easy for many of you maths bods, but whats
e^(-kt ln m)

is it m^-kt ? if so ive got the wrong answer lol
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17 years ago
#2
(Original post by edders)
ok i know this will be easy for many of you maths bods, but whats
e^(-kt ln m)

is it m^-kt ? if so ive got the wrong answer lol
yes it is, but where is the integration? you had my hopes up!
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#3
(Original post by elpaw)
yes it is, but where is the integration? you had my hopes up!
lol oh yeah good point... thats the result of an integration.
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#4
this is the source of the problem i think...

int -k [(1/m) dt]

is it -k[t ln m ]
0
17 years ago
#5
(Original post by edders)
this is the source of the problem i think...

int -k [(1/m) dt]

is it -k[t ln m ]
no, it is just -k t/m (unless m is a function of t, which would make it more complicated)
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17 years ago
#6
(Original post by edders)
this is the source of the problem i think...

int -k [(1/m) dt]

is it -k[t ln m ]
Why have you integrated with respect to m?

Ben
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#7
(Original post by Ben.S.)
Why have you integrated with respect to m?

Ben
because im ignorant?
0
17 years ago
#8
it's reading threads like this that i panic that i've applied for a degree that's half maths...

lou xxx
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#9
(Original post by lou p lou)
it's reading threads like this that i panic that i've applied for a degree that's half maths...

lou xxx
have you done AS/are doing A2 lou?
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#10
(Original post by elpaw)
no, it is just -k t/m (unless m is a function of t, which would make it more complicated)
so when youre integrating stuff, you just do the stuff its wrt... ignoring the other variables?
0
17 years ago
#11
(Original post by edders)
so when youre integrating stuff, you just do the stuff its wrt... ignoring the other variables?
yes, that is why they are called constants. (if i didn't know any better, i could swear maskall has hacked into your account....., you're starting to sound like him)
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#12
(Original post by elpaw)
yes, that is why they are called constants. (if i didn't know any better, i could swear maskall has hacked into your account....., you're starting to sound like him)
i didnt use the word constant, i said variable 'ignore the other variables' m is a variable in this case
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17 years ago
#13
(Original post by edders)
i didnt use the word constant, i said variable 'ignore the other variables' m is a variable in this case
it depends on if the variable is dependent on the w.r.t, or if it is independent (which is otherwise known as a constant).
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17 years ago
#14
(Original post by edders)
ok i know this will be easy for many of you maths bods, but whats
e^(-kt ln m)

is it m^-kt ? if so ive got the wrong answer lol
e^(-kt ln m)=(e^ln m)^-kt=m^-kt
0
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