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    This is the Q,

    Cocl2 = co + cl2

    9.90 g of cocl2 was placed in a 500 cm3 vessel at 500 k and allowed to come to equilibrium. At this time 0.0706g of co was found to be presen. Calculate the Kc....


    Okay, I know all the basics really like how to find the equilibrium concentrations but, is it necessary to convert the molar values to mol/dm-3 for the Kc expression? How do you do that without the volumes...is grams directly proportional to cubic centimetres...I suspose I am confusing myself :confused:
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    (Original post by Blamps)
    This is the Q,

    Cocl2 = co + cl2

    9.90 g of cocl2 was placed in a 500 cm3 vessel at 500 k and allowed to come to equilibrium. At this time 0.0706g of co was found to be presen. Calculate the Kc....


    Okay, I know all the basics really like how to find the equilibrium concentrations but, is it necessary to convert the molar values to mol/dm-3 for the Kc expression? How do you do that without the volumes...is grams directly proportional to cubic centimetres...I suspose I am confusing myself :confused:
    Don't take the mick cos I hate number crunching
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    (Original post by Blamps)
    This is the Q,

    Cocl2 = co + cl2

    9.90 g of cocl2 was placed in a 500 cm3 vessel at 500 k and allowed to come to equilibrium. At this time 0.0706g of co was found to be presen. Calculate the Kc....


    Okay, I know all the basics really like how to find the equilibrium concentrations but, is it necessary to convert the molar values to mol/dm-3 for the Kc expression? How do you do that without the volumes...is grams directly proportional to cubic centimetres...I suspose I am confusing myself :confused:

    Convert to mol/dm^3. The moles of CO and Cl2 @ eq are equal and can be found by calculation.
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    (Original post by Ralfskini)
    Convert to mol/dm^3. The moles of CO and Cl2 @ eq are equal and can be found by calculation.
    How do you do the former with just the info given in the Q
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    (Original post by Blamps)
    How do you do the former with just the info given in the Q
    because it is a 1:1 ratio equation
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    (Original post by elpaw)
    because it is a 1:1 ratio equation
    No...I mean how can you convert from moles to mol/dm-3
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    (Original post by elpaw)
    because it is a 1:1 ratio equation
    Finding the concentrations at equilibrium though is not reliant on the ratios
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    (Original post by Blamps)
    No...I mean how can you convert from moles to mol/dm-3
    divide by 0.5 (500 cm³)
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    (Original post by elpaw)
    divide by 0.5 (500 cm³)
    That's where I got slightly confused...thanks anyway...
 
 
 

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