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# Help...equilibrium constant watch

1. This is the Q,

Cocl2 = co + cl2

9.90 g of cocl2 was placed in a 500 cm3 vessel at 500 k and allowed to come to equilibrium. At this time 0.0706g of co was found to be presen. Calculate the Kc....

Okay, I know all the basics really like how to find the equilibrium concentrations but, is it necessary to convert the molar values to mol/dm-3 for the Kc expression? How do you do that without the volumes...is grams directly proportional to cubic centimetres...I suspose I am confusing myself
2. (Original post by Blamps)
This is the Q,

Cocl2 = co + cl2

9.90 g of cocl2 was placed in a 500 cm3 vessel at 500 k and allowed to come to equilibrium. At this time 0.0706g of co was found to be presen. Calculate the Kc....

Okay, I know all the basics really like how to find the equilibrium concentrations but, is it necessary to convert the molar values to mol/dm-3 for the Kc expression? How do you do that without the volumes...is grams directly proportional to cubic centimetres...I suspose I am confusing myself
Don't take the mick cos I hate number crunching
3. (Original post by Blamps)
This is the Q,

Cocl2 = co + cl2

9.90 g of cocl2 was placed in a 500 cm3 vessel at 500 k and allowed to come to equilibrium. At this time 0.0706g of co was found to be presen. Calculate the Kc....

Okay, I know all the basics really like how to find the equilibrium concentrations but, is it necessary to convert the molar values to mol/dm-3 for the Kc expression? How do you do that without the volumes...is grams directly proportional to cubic centimetres...I suspose I am confusing myself

Convert to mol/dm^3. The moles of CO and Cl2 @ eq are equal and can be found by calculation.
4. (Original post by Ralfskini)
Convert to mol/dm^3. The moles of CO and Cl2 @ eq are equal and can be found by calculation.
How do you do the former with just the info given in the Q
5. (Original post by Blamps)
How do you do the former with just the info given in the Q
because it is a 1:1 ratio equation
6. (Original post by elpaw)
because it is a 1:1 ratio equation
No...I mean how can you convert from moles to mol/dm-3
7. (Original post by elpaw)
because it is a 1:1 ratio equation
Finding the concentrations at equilibrium though is not reliant on the ratios
8. (Original post by Blamps)
No...I mean how can you convert from moles to mol/dm-3
divide by 0.5 (500 cm³)
9. (Original post by elpaw)
divide by 0.5 (500 cm³)
That's where I got slightly confused...thanks anyway...

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