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help on M1 question
yo i was on an m1 question, da nov 03 question 3
it says that "a heavy suitcase S of mass 50kg is moving through along a horizontal floor under the action of a force of magnitide P newtons. the force acts at 30degrees to the floor and S moves in a straight line at constant speed. the suitcase is modelled as a particle and the floor as a rough horizontal plane. the coeficent of frictin is 0.6"
my problem is dat i wud hav thought that the normal reaction force woulld be R=50g - Psin30 but da markscheme says that its R=50g + Psin30. And i dnt see y. any explanantion would be most appreciated.
it says that "a heavy suitcase S of mass 50kg is moving through along a horizontal floor under the action of a force of magnitide P newtons. the force acts at 30degrees to the floor and S moves in a straight line at constant speed. the suitcase is modelled as a particle and the floor as a rough horizontal plane. the coeficent of frictin is 0.6"
my problem is dat i wud hav thought that the normal reaction force woulld be R=50g - Psin30 but da markscheme says that its R=50g + Psin30. And i dnt see y. any explanantion would be most appreciated.
jam_boy
yo i was on an m1 question, da nov 03 question 3
it says that "a heavy suitcase S of mass 50kg is moving through along a horizontal floor under the action of a force of magnitide P newtons. the force acts at 30degrees to the floor and S moves in a straight line at constant speed. the suitcase is modelled as a particle and the floor as a rough horizontal plane. the coeficent of frictin is 0.6"
my problem is dat i wud hav thought that the normal reaction force woulld be R=50g - Psin30 but da markscheme says that its R=50g + Psin30. And i dnt see y. any explanantion would be most appreciated.
it says that "a heavy suitcase S of mass 50kg is moving through along a horizontal floor under the action of a force of magnitide P newtons. the force acts at 30degrees to the floor and S moves in a straight line at constant speed. the suitcase is modelled as a particle and the floor as a rough horizontal plane. the coeficent of frictin is 0.6"
my problem is dat i wud hav thought that the normal reaction force woulld be R=50g - Psin30 but da markscheme says that its R=50g + Psin30. And i dnt see y. any explanantion would be most appreciated.
The force P acts downwards.
Resolve vertically;
R - 50g - Psin30 = 0
R = 50g + Psin30
I got the same as you first time round - reckon the question's not being clear as to which direction P is pointing in: see the attachment, they're prob thinking of bottom sketch whereas top one what you and me had in mind.
oceane
I got the same as you first time round - reckon the question's not being clear as to which direction P is pointing in: see the attachment, they're prob thinking of bottom sketch whereas top one what you and me had in mind.
the top sketch is wrong.
The suitcase isn't attached to a string/rope as the question doesn't say so, so the force has to act from the back of the suitcase, not the front.
endeavour
It makes no difference. (You can pull a suitcase too!)
i suppose so.
I still would have gone for the bottom diagram.
I've just found the paper and the question gives you a diagram so all this discussion was for nothing.
Widowmaker
I've just found the paper and the question gives you a diagram so all this discussion was for nothing.
Yeah you were right, sorry -it does make a difference when resolving vertically and the question says to the floor.
There's a vertical component of P which acts vertically downwards (Psin30)
Forces acting up = forces acting down as it's equilibrium
R = 50g + Psin30
Forces acting up = forces acting down as it's equilibrium
R = 50g + Psin30
jam_boy
yh, resolving p vertically gives psin30 right,i see dat psin30 + da normal reaction counterbalance the weight of the suitcase, thanks 4 ur help
no, you are still getting confused with directions.
The normal reaction counterbalances the weight and the force Psin30, since the vertical motion perpendicular to the horizontal motion = 0.
so whats P = ?
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