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M1 - Dynamics
The diagram shows a particle A of mass 0.5Kg suspended by a vertical string. A particle B of mass 0.4 kg is suspended from A by means of another string. A force of 10 N is applied to the upper string and the particles move upwards. Find the tension in the lower string and the acceleration of the system.
The rest of the quests I can do but, it seems questions of this type I can't. Please can someone connotate the method to me. Thanks
10N
|
|
----
| |A 0.5 Kg
----
|
|
----
| | B 0.4 Kg
----
The rest of the quests I can do but, it seems questions of this type I can't. Please can someone connotate the method to me. Thanks
10N
|
|
----
| |A 0.5 Kg
----
|
|
----
| | B 0.4 Kg
----
w0rldl3ad3r
The diagram shows a particle A of mass 0.5Kg suspended by a vertical string. A particle B of mass 0.4 kg is suspended from A by means of another string. A force of 10 N is applied to the upper string and the particles move upwards. Find the tension in the lower string and the acceleration of the system.
The rest of the quests I can do but, it seems questions of this type I can't. Please can someone connotate the method to me. Thanks
10N
|
|
----
| |A 0.5 Kg
----
|
|
----
| | B 0.4 Kg
----
The rest of the quests I can do but, it seems questions of this type I can't. Please can someone connotate the method to me. Thanks
10N
|
|
----
| |A 0.5 Kg
----
|
|
----
| | B 0.4 Kg
----
The magnitude of the tension in the string between AB is constant in magnitude throughout its length.
Now what does this force do?
i) It is the force pulling B upwards
ii) it is pulling back and hindering A.
(I would mark a force T pulling down on A, and a force T pulling up on B)
Take the direction of motion as positive ( upwards in this case); and consider the particles independently, and in turn, appling Newtons 2nd law ( F = ma)
Considering A
10 - T - 0.5g = 0.5a
Considering B
T - 0.4g = 0.4a
You now have a pair of simultaneous equations in T and a.
Add the equations to give:
10 - 0.5g - 0.4g = 0.5a + 0.4a
10 - 0.9g = 0.9a
100 -9g = 9a
100 - 98 = 9a
2 = 9a
a=2/9
Use this to find T
T - 0.4g = 2/9
etc....
MrM.
100 -9g = 9a
100 - 98 = 9a
OOPS CARELESS MISTAKE HERE
9 x 9.8 is not 98 of course.......
It should have been 88.2
then
100 - 88.2 = 9a etc
Mrm.
100 - 98 = 9a
OOPS CARELESS MISTAKE HERE
9 x 9.8 is not 98 of course.......
It should have been 88.2
then
100 - 88.2 = 9a etc
Mrm.
Fantastic thank you Mrm
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can someone please explain what principle domain is and why the answer is a not c?Maths
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