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# I'm Going Daft Ere. - Maths. watch

1. Alright so I'm going daft at this minute in time:

INT 4 (x^2 - 1)^-2 dx

Because my mind has gone totally blank on how to do something that appears so simple ?!
2. (Original post by edders)
well tell us the answer then oh great maths genius
anyway, have you got your interview invite yet?
3. (Original post by elpaw)
anyway, have you got your interview invite yet?
sun 14th dec, interviewed in the afternoon
4. (Original post by edders)
sun 14th dec, interviewed in the afternoon
just one interview?
5. (Original post by elpaw)
just one interview?
more than one i would have thought as its joint honours (phys and phil)... anyway sun afternoon is the first one.
6. (Original post by edders)
more than one i would have thought as its joint honours (phys and phil)... anyway sun afternoon is the first one.
they will probably go on till tuesday.
7. (Original post by Expression)
Alright so I'm going daft at this minute in time:

INT 4 (x^2 - 1)^-2 dx

Because my mind has gone totally blank on how to do something that appears so simple ?!
have you tried letting x = cosh t? dunno if it'll work, but it looks like it may well do...
8. you can split the denominator into (x+1)(x-1)

Code:
```-x         Log[-1 + x]   Log[1 + x]
-----------  - ----------- + ----------
2 (x² - 1)          4            4```
9. how did you do that?
10. (Original post by edders)
how did you do that?
Mathematica hehehe
11. (Original post by Expression)
Alright so I'm going daft at this minute in time:

INT 4 (x^2 - 1)^-2 dx

Because my mind has gone totally blank on how to do something that appears so simple ?!
on the aim test is it?

97% in the one due in like 7 minutes, get in there!

12. (Original post by byb3)
on the aim test is it?

97% in the one due in like 7 minutes, get in there!

Nice one, I did sort it in the end, didn't quite get 97 % though, amazing how many numerical errors you can make using partial fractions.

The AiM system isn't very helpful really, it should be able to recognize places at which errors creep in, rather than just being plain right or plain wrong with no advice on where the error lies!

It was just a mental block where even the nice stuff didn't appear nice - soon solved by watching a couple of episodes of CSI as stimulation, with a coffee, and suddenly I was a bit better !
13. what's AiM?
14. (Original post by elpaw)
what's AiM?
Assessed Interactive Mathematics.

Tis a mechanism of constant assessment, which marks itself, using the software of the Mathematical programme Maple to check for the correct answer.
15. (Original post by Expression)
Assessed Interactive Mathematics.

Tis a mechanism of constant assessment, which marks itself, using the software of the Mathematical programme Maple to check for the correct answer.
to make sure errors don't creep in I always validate my answers now. So it shows you exactly what it thinks you have typed. I used to just mark them straight away and get a few incorrect answers here and again simply due to omitting brackets from a negative square root!

At least you don't have to do bloody PAS153....I despise PAS151 just as much. Why did I pick it? I have no idea.
16. (Original post by Expression)
Alright so I'm going daft at this minute in time:

INT 4 (x^2 - 1)^-2 dx

Because my mind has gone totally blank on how to do something that appears so simple ?!
It can be factorised into some simple terms.
substitution of x= tant will do as well, but takes more time
17. (Original post by byb3)
to make sure errors don't creep in I always validate my answers now. So it shows you exactly what it thinks you have typed. I used to just mark them straight away and get a few incorrect answers here and again simply due to omitting brackets from a negative square root!

At least you don't have to do bloody PAS153....I despise PAS151 just as much. Why did I pick it? I have no idea.
You picked PAS153 as an elective ?!

I've heard that that could be tough.

Makes you wonder how far they can go with that though, given that we have PAS152 in Spring.
18. I got:
Code:
`ln|x+1| - ln|x-1| - 1/(x+1) - 1/(x-1)`
Use partial fractions

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