Hess' Law -> Calculate enthalpy change of Fermentation of Glucose

Yo yo yo homies,

Was rollin' through some chemistry papers earlier after a hard night partying and I found this mad ass question that I can't boss! My teacher said she's gonna pop a cap in my ass if I dont do them!

>Calculate the enthalpy change during the fermentation of glucose given the enthalpy change of combustion for glucose is -2820 and the enthalpy change of combustion for ethanol is -1368.

C6H12O6 ->2C2H5OH + 2CO2
(Sorry bout the lack of subscript)

>Explain why the vats in fermentation are fitted with copper pipes to promote cooooling.

I got the first answer to be +704KJ/mol, but it mayy be wrong

Cheers homeboys

go from reactants to products via the combustion products

-2820 - (2 x-1368) = -84 kJ

Nah dawg, you missed off the 2CO2

btw its formation not fermentation

No, look at the reaction, it's a fermentation.

Formation reaction is forming one mole of a compound from it's elements in their standard states.

You thought about my solution RamJamMan?

You still here charco? Seen you on lots of posts!

Did you not notice the date of the post - it's twelve years ago...