Original post by iamspiderman
Don't understand how to work out this
Question??
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Don't understand how to work out this
Question??
The question is asking you to work out the enthalpy change for the given equation, which essentially means work out the enthalpy change in J/mol. To start off, you'll want to work out the enthalpy change for the experiment using .
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(edited 7 years ago)
Original post by iamspiderman
Ok thanks
There is no mass given so would I need to divide the 2.00 mol dm-3 by the molar mass of cuso4 to get it?
There is no mass given so would I need to divide the 2.00 mol dm-3 by the molar mass of cuso4 to get it?
We're not given the mass but we can work it out. We're given the volume of copper sulfate solution (100ccm) and the density (1g/ccm) and you can work out the mass from this.
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(edited 7 years ago)
Original post by iamspiderman
Ok so the mass is 100g
So it will be 100 x 4.18 x 45 = 18,810 ?
So it will be 100 x 4.18 x 45 = 18,810 ?
Yes, that's the for the experiment. You now need to work it out in terms of J/mol.
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