I'm guessing the relevant reaction is: 2NH4OH + H2SO4 -> (NH4)2SO4 + 2H2O
First calculate moles of ammonium hydroxide: mol = mass/mr = 70/(14+4+16+1) = 2 2:1 ratio of NH4OH to (NH4)2SO4 means 1 mol (NH4)2SO4 mass = mol*mr = 1*(2(14+4) + 32 + 16*4) = 132g