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Urgent: Calculating units for Van der Waals equation
"A laboratory gas clyinder filled with nitrogen has a volume of 0.15 m³ and contains 35 kg of gas when delivered. Calculate the pressure in units of atmospheres inside the clyinder at 20°C using the van der Waals equation.
The van der Waals constants for nitrogen are a = 1.408 atm dm6 mol² and b = 0.0391 dm³ mol1, R = 0.08206 dm³ atm K-1 mol-1."
I can substitute the numbers into the equation can get an answer. However I am having problems showing that the units cancel to just atm, could someone show me how
.
Thanks
I meant to attach it earlier lol
The van der Waals constants for nitrogen are a = 1.408 atm dm6 mol² and b = 0.0391 dm³ mol1, R = 0.08206 dm³ atm K-1 mol-1."
I can substitute the numbers into the equation can get an answer. However I am having problems showing that the units cancel to just atm, could someone show me how
.Thanks
I meant to attach it earlier lol
moojoo
If you tell me what the Van der Waals equation is, then i might be able to help
Lol thanks
moojoo
If you tell me what the Van der Waals equation is, then i might be able to help
Thanks for the offer but I have sorted the problem, the workshop sheet, had incorrect indices on, just found a table in the text book and have been able to cancel the units to atm. Never trust lecturers
Ah ok, substituting those units into the equation I Get the following:
p = mol dm3 atm k-1 mol-1 k - atm dm6 mol-2 mol2
dm3 - mol dm3 mol-1 dm6
on the left part, everything cancels on the bottom you may have gone wrong a bit, you are left with dm3 - dm3 which is dm3 still, an that cancels
on the right everthing cancels, leaving atm
so overall:
atm - atm, which is just atm
does that help? (sorry for the non mathematical writing!)
p = mol dm3 atm k-1 mol-1 k - atm dm6 mol-2 mol2
dm3 - mol dm3 mol-1 dm6
on the left part, everything cancels on the bottom you may have gone wrong a bit, you are left with dm3 - dm3 which is dm3 still, an that cancels
on the right everthing cancels, leaving atm
so overall:
atm - atm, which is just atm
does that help? (sorry for the non mathematical writing!)
atm - atm = 0? not atm?
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