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Chemistry ISA Help? (Past ISA Question)

***Before the moderators become aroused, this from a past ISA paper from 2011*** :colondollar:

Hi everyone, I am really confused on this question for AQA AS Chemistry ISA, the exam paper is from 2011 and I need to know the process to get to the answer on this question:

The equation for the reaction between sulfuric(IV) acid and sodium hydroxide is shownbelow.
H2SO3 + 2NaOH Na2SO3 + 2H2O
Use your answers from Questions 1 and 2 and the equation above to calculate theconcentration, in mol dm–3, of sulfuric(IV) acid in solution A.
Give your answer to the appropriate precision.

(Question 1 = 28.85)
(Question 2 = 2.5 x 10^3)

Help would be appreciated, I would be extremely grateful as I have my ISA soon. Thank You.

Reply 1

mattcandy3

It would really help if you also gave question 1 and 2 and not just an answer, as then i dont have any background info to what these numbers mean. thanks/

Reply 2

TSR George

Original post by mattcandy3

It would really help if you also gave question 1 and 2 and not just an answer, as then i dont have any background info to what these numbers mean. thanks/

Question 1 is: Average titre

Question 2 is: The concentration of the sodium hydroxide solution used was 0.100 mol dm–3.Calculate the amount, in moles, of NaOH in 25.0 cm3 of this sodium hydroxidesolution.

Reply 3

THEMathlete

concentration = moles/ (average titre/1000)

Reply 4

ccalby

Moles = Concentration x Volume (N=CV)

Concentration = Moles / Volume

Remember concentration is Moldm-1
Remember volume is dm3 (so to get from cm3 to dm3, divide by 1000)

Reply 5

ccalby

Moles = Concentration x Volume (N=CV)

Concentration = Moles / Volume

Remember concentration is Moldm-1
Remember volume is dm3 (so to get from cm3 to dm3, divide by 1000)