Enthalpy Changes??
2.78g of potassium carbonate
30 ml of 2.00 mol dm-3 of HCl
temperature change= +6 degrees
Can someone explain each step of calculating the enthalpy change? Thanks
30 ml of 2.00 mol dm-3 of HCl
temperature change= +6 degrees
Can someone explain each step of calculating the enthalpy change? Thanks
(edited 9 years ago)
Q=mc(deltaT)
(deltaH)=Q/n
(deltaH)=Q/n
Original post by Infraspecies
Q=mc(deltaT)
(deltaH)=Q/n
(deltaH)=Q/n
I know the equation but when I have it I seem to struggle- I don't understand when you use the measurements of the reactants
2.78g of potassium carbonate
30 ml of 2.00 mol dm-3 of HCl
temperature change= +6 degrees
Can someone explain each step of calculating the enthalpy change? Thanks
30 ml of 2.00 mol dm-3 of HCl
temperature change= +6 degrees
Can someone explain each step of calculating the enthalpy change? Thanks
Original post by Pigster
What do all the letters refer to?
Q = ?
m = ?
c = ?
T = ?
n = ?
Q = ?
m = ?
c = ?
T = ?
n = ?
Q = Energy Transferred (J)
m =Mass (kg)
c= Specific Latent Heat
Delta T= Temperature change
n= I don't have any clue,that not in my formula
n = amount i.e. n = m/Mr (or n = m/RFM, et.al. depending on what you're taught)
You're trying to work out delta H, enthalpy change PER MOLE. To work that out, you work out the energy change, then divide that by the number of moles you have.
Also, mass is in g in chemistry. They tend to use kg in physics.
You're trying to work out delta H, enthalpy change PER MOLE. To work that out, you work out the energy change, then divide that by the number of moles you have.
Also, mass is in g in chemistry. They tend to use kg in physics.
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