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Stupid Mol at Equilibrim doubt. HELP!

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    can someone please tell how you find mol at eqilibrium for H2?
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    moles of reactant at equilibrium = initial moles - moles reacted
    moles of product at equilibrium = initial moles + moles formed

    We can see that the moles formed is 38.5 (as moles of CH3OH went from 0 to 38.5)
    Moles of hydrogen = 77.5 - (2 x 38.5)
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